用文件名替换文件中的静态字符串的批处理脚本 [英] Batch script that replaces static string in file with filename

问题描述

我在c:\data\中有3000个文件，我需要用文件名替换每个文件中的静态字符串.例如，在文件12345678.txt中将有一些记录以及字符串99999999，我想用文件名12345678替换99999999.

I have 3000 files in c:\data\, and I need to replace a static string in each of them with the name of the file. For example, in the file 12345678.txt there will be some records along with the string 99999999, and I want to replace 99999999 with the filename 12345678.

如何使用批处理脚本执行此操作?

How can I do this using a batch script?

推荐答案

尝试一下，

replace_string="99999999"
for f in *.txt; do
    sed -i "s/${replace_string}/${f%.*}/g" "$f";
done

说明:

• for f in *.txt; do ... done:循环浏览当前目录中名为*.txt的文件.
• sed -i ... file就地编辑file (-i).
• "s/pattern/replacement/g"替换(s)模式，并在全局范围内(g)替换 .
• ${f%.*}不带扩展名的文件名(通过)

• for f in *.txt; do ... done: Loop through files named *.txt in current directory.
• sed -i ... file Edit file in place (-i).
• "s/pattern/replacement/g" Substitutes (s) pattern with replacement globally (g).
• ${f%.*} Filename without extension (via)

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