在Scala 2.8中打包private修饰符 [英] Package private modifier in Scala 2.8

问题描述

如果我尝试

private[com.company.foo] def bar(xml: XmlPath) = {

我知道

[error]     ... ']' expected but '.' found.
[error]     private[com.
[error]                ^

那是什么?我只能将其打包私有给com.*，否则...?

What's with that? I can only make it package-private to com.*, or...?

推荐答案

您只能定义其中定义了代码的封装包:

You can only define the enclosing package, within which the code is defined:

package com.company.foo

class Bar{
  private[foo] def bar(xml: XmlPath)
}    

，如果要将其设置为公司:

and if you want to set it to company:

private[company] def bar(xml: XmlPath)

这篇关于在Scala 2.8中打包private修饰符的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！