在 Scala 2.8 中打包私有修饰符 [英] Package private modifier in Scala 2.8

问题描述

如果我尝试

private[com.company.foo] def bar(xml: XmlPath) = {

我明白了

[error]     ... ']' expected but '.' found.
[error]     private[com.
[error]                ^

那是怎么回事?我只能将它设为 com.* 的包私有，还是...?

What's with that? I can only make it package-private to com.*, or...?

推荐答案

你只能定义封闭包，在里面定义代码:

You can only define the enclosing package, within which the code is defined:

package com.company.foo

class Bar{
  private[foo] def bar(xml: XmlPath)
}    

如果您想将其设置为公司:

and if you want to set it to company:

private[company] def bar(xml: XmlPath)

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