重涂而不清除 [英] Repaint without clearing

问题描述

我正在研究一个模仿Paint的程序.问题是当我绘制一个新形状时，以前的形状会被删除.我试图注释掉我的paintComponents超级调用，该调用可以正常工作，但是留下了过多的绘图.

I am working on a program that mimics Paint. The problem is when I draw a new shape the previous shape gets deleted. I tried to comment out my super call of paintComponents which works but leaves behind too much drawing.

import java.awt.Color;
import java.awt.Dimension;
import java.awt.Graphics;
import java.awt.event.MouseEvent;
import java.awt.event.MouseListener;
import java.awt.event.MouseMotionListener;

import javax.swing.JOptionPane;
import javax.swing.JPanel;


public class Canvas1 extends JPanel{

    Circle c;
    Rectangle r;
    Line l;
    String str;
    int x1,x2,y1,y2;
    Graphics g;
    int draw;
    int hollow=0;
    Color cc;


    public Canvas1(){

        LineListener listener = new LineListener();
        addMouseListener(listener);
        addMouseMotionListener(listener);


        setBackground (Color.white);
        setPreferredSize (new Dimension(400, 400));

    }

    public void paintComponent(Graphics g){
        super.paintComponent(g);
        g.setColor(cc);
        if (this.draw == 1)
        {
            c = new Circle (x1,y1,x2,y2);
            if (hollow == 0)
            {
                c.hollow = false;
            }
            if (hollow == 1)
            {
                c.hollow = true;
            }
            c.draw(g);
        }
        if (this.draw ==2)
        {
            r = new Rectangle (x1,y1,x2,y2);
            if (hollow == 0)
            {
                r.hollow = false;
            }
            if (hollow == 1)
            {
                r.hollow = true;
            }   
            r.draw(g);
        }
        if (this.draw ==0)
        {
            l = new Line(x1,y1,x2,y2);
            l.draw(g);
        }
        if (this.draw ==3)
        {
            g.drawString(str, x1, y1);
        }

    }
    public void update(Graphics g) {
        paint(g);
        }
    private class LineListener implements MouseListener, MouseMotionListener{

        public void mousePressed(MouseEvent event){
            x1 = event.getX();
            y1 = event.getY();
            if (draw ==3)
            {
                str = JOptionPane.showInputDialog("Enter String");
                repaint();
            }
        }

        public void mouseDragged(MouseEvent event){
            if (draw ==1 || draw==2)
            {
                x2 = event.getX()-x1;
                y2 = event.getY()-y1;
            }
            if (draw ==0)
            {
                x2 = event.getX();
                y2 = event.getY();
            }
            repaint();

        }

        public void mouseClicked (MouseEvent event) {

        }
        public void mouseReleased (MouseEvent event) {
            if (draw ==1 || draw==2)
            {
                x2 = event.getX()-x1;
                y2 = event.getY()-y1;
            }
            if (draw ==0)
            {
                x2 = event.getX();
                y2 = event.getY();
            }
        }
        public void mouseEntered (MouseEvent event) {}
        public void mouseExited (MouseEvent event) {}
        public void mouseMoved (MouseEvent event) {}
    }
}

推荐答案

如所发现的，您需要调用super.paintComponent(g)，否则，JPanel背景不会被绘制，并且一切都是一团糟.问题在于，由于draw字段只能是单个值，因此一次只能绘制一个形状.一种解决方案是创建形状的ArrayList，并在paintComponent中的List中绘制每个形状.

As you've discovered, you need to call super.paintComponent(g), otherwise, the JPanel background doesn't get painted and everything is a mess. The problem is that only one shape can be drawn at any one time as the draw field can only be a single value. One solution would be to create an ArrayList of shapes and draw each shape in the List in paintComponent.

• 示例

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