pandas -指数值的返回列 [英] pandas - return column of exponential values

问题描述

从示例数据帧df开始，例如:

Starting from a sample dataframe df like:

a,b
0,0.71
1,0.75
2,0.80
3,0.90

我将添加具有列b的指数值的新列.到目前为止，我尝试过:

I would add a new column with exponential values of column b. So far I tried:

df['exp'] = math.exp(df['b'])

但是此方法返回:

"cannot convert the series to {0}".format(str(converter)"
TypeError: cannot convert the series to <type 'float'>

是否可以将math函数应用于整个列?

Is there a way to apply a math function to a whole column?

推荐答案

math.exp无法理解Series数据类型，请使用numpy

Well math.exp doesn't understand Series datatype, use numpy np.exp which does and is vectorised so operates on the entire column:

In [24]:
df['exp'] = np.exp(df['b'])
df

Out[24]:
   a     b       exp
0  0  0.71  2.033991
1  1  0.75  2.117000
2  2  0.80  2.225541
3  3  0.90  2.459603

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