打印在C用printf常量指数值 [英] Print constant exponent value using printf in c

问题描述

我用％E 格式说明。试图％3.2E 或％4.3E 。

I used %e format specifier. Tried %3.2e or %4.3e.

例如：结果
如果 VAR = 0.001342 ，那么我想打印 0.1342e-02 。但是版画 1.342e-03 结果
如果 VAR = 0.543124 ，那么我想打印 54.3124e-02 。但是版画 5.43124e-01 结果
如果 VAR = 0.0123653 ，那么我想打印 1.23653e-02 。

Example:
if var=0.001342, then I want to print 0.1342e-02. But prints 1.342e-03
if var=0.543124, then I want to print 54.3124e-02. But prints 5.43124e-01
if var=0.0123653, then I want to print 1.23653e-02.

这是什么都可能的价值，我只想解决我的指数值的打印结果。

That is what ever maybe the value, I just want to fix my exponent value an print the result.

推荐答案

这本手册：

EE 双参数圆润，并在风格转换
               [ - ] + d.ddde -dd哪里有小数点前有一位
               字符和数字的数以后它等于precision;如果precision丢失，它被当作6;如果
               precision是零，没有出现小数点字符。一个E转换使用字母 E'（而不是 E'）介绍
               指数。该指数总是包含至少两个数字;如果
               值为零，指数是00。

eE The double argument is rounded and converted in the style [-]d.ddde+-dd where there is one digit before the decimal-point character and the number of digits after it is equal to the precision; if the precision is missing, it is taken as 6; if the precision is zero, no decimal-point character appears. An E conversion uses the letter E' (rather thane') to introduce the exponent. The exponent always contains at least two digits; if the value is zero, the exponent is 00.

EE 为科学记数法，所以在只有一个非NUL位小数点。

eE is for the scientific notation, so only one non nul digit before the decimal point.

您需要自己进行转换，如：

You need to make the conversion by yourself, like:

float number = 0.01023;
float normalized = number*100;
int mantissa_int_part = normalized;
int mantissa_decimal_part = (normalized-mantissa_int_part)*10000;
printf("%02d.%04d e-2",mantissa_int_part,mantissa_decimal_part);

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