从列表创建 pandas 排列的数据框 [英] Create a dataframe of permutations in pandas from list
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问题描述
我有以下列表:
aa = ['aa1', 'aa2', 'aa3', 'aa4', 'aa5']
bb = ['bb1', 'bb2', 'bb3', 'bb4', 'bb5']
cc = ['cc1', 'cc2', 'cc3', 'cc4', 'cc5']
我想这样创建一个熊猫数据框:
I want to create a pandas dataframe as such:
aa bb cc
aa1 bb1 cc1
aa2 bb1 cc1
aa3 bb1 cc1
aa4 bb1 cc1
aa5 bb1 cc1
aa1 bb2 cc1
aa1 bb3 cc1
aa1 bb4 cc1
aa1 bb5 cc1
aa1 bb1 cc2
aa1 bb1 cc3
aa1 bb1 cc4
aa1 bb1 cc5
我对如何执行此操作感到困惑. 我看了一些例子: 如何在Python中生成列表的所有排列
I'm stuck as to how to do this. I've looked at examples: How to generate all permutations of a list in Python
我可以使用以下方法分别进行每个排列:
I can do each permutation individually using:
import itertools
itertools.permutations(['aa1','aa2','aa3','aa4','aa5'])
我有几十个列表,理想情况下,我想自动执行.
I have a few tens of lists and ideally, I'd like to do them automatically.
感谢任何帮助!
推荐答案
我相信您需要itertools.product
,而不是permutations
.
I believe you need itertools.product
, not permutations
.
In [287]: lists = [aa, bb, cc]
In [288]: pd.DataFrame(list(itertools.product(*lists)), columns=['aa', 'bb', 'cc'])
Out[288]:
aa bb cc
0 aa1 bb1 cc1
1 aa1 bb1 cc2
2 aa1 bb1 cc3
3 aa1 bb1 cc4
4 aa1 bb1 cc5
5 aa1 bb2 cc1
6 aa1 bb2 cc2
7 aa1 bb2 cc3
8 aa1 bb2 cc4
...
这将为您提供列表的笛卡尔积.到目前为止,列名已经过硬编码,但是您可以使用df.rename
动态重命名它们.
This will give you the Cartesian product of your lists. As of now, the column names are hardcoded, but you can use df.rename
to dynamically rename them.
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