numpy中的多个插入,其中成对的元素没有子文本 [英] Multiple inserts in numpy where paired elements don't have subtext
问题描述
此问题在此以前的帖子中继续由@ecortazar回答.但是,我也想在不包含特定字符串的pd.Series的两个元素之间粘贴,仅使用Pandas/Numpy.注意:文本中所有带有href
的行都是不同的.
This question follows up on this previous post answered by @ecortazar. However, I'd also like to paste between two elements in a pd.Series which did not include a certain string, using Pandas / Numpy only. Note: All lines with href
in the text are different.
import pandas as pd
import numpy as np
table = pd.Series(
["<td class='test'>AA</td>", # 0
"<td class='test'>A</td>", # 1
"<td class='test'><a class='test' href=...", # 2
"<td class='test'>B</td>", # 3
"<td class='test'><a class='test' href=...", # 4
"<td class='test'>BB</td>", # 5
"<td class='test'>C</td>", # 6
"<td class='test'><a class='test' href=...", # 7
"<td class='test'>F</td>", # 8
"<td class='test'>G</td>", # 9
"<td class='test'><a class='test' href=...", # 10
"<td class='test'>X</td>"]) # 11
dups = ~table.str.contains('href') & table.shift(-1).str.contains('href')
array = np.insert(table.values, dups[dups].index, "None")
pd.Series(array)
# OUTPUT:
# 0 <td class='test'>AA</td>
# 1 None
# 2 <td class='test'>A</td>
# 3 <td class='test'><a class='test' href=...
# 4 None Incorrect
# 5 <td class='test'>B</td>
# 6 <td class='test'><a class='test' href=...
# 7 <td class='test'>BB</td>
# 8 None
# 9 <td class='test'>C</td>
# 10 <td class='test'><a class='test' href=...
# 11 <td class='test'>F</td>
# 12 None
# 13 <td class='test'>G</td>
# 14 <td class='test'><a class='test' href=...
# 15 <td class='test'>X</td>
这是我想要的实际文本输出.
Here is the actual text output I'd like.
# OUTPUT:
# 0 <td class='test'>AA</td>
# 1 None
# 2 <td class='test'>A</td>
# 3 <td class='test'><a class='test' href=...
# 4 <td class='test'>B</td>
# 5 <td class='test'><a class='test' href=...
# 6 <td class='test'>BB</td>
# 7 None
# 8 <td class='test'>C</td>
# 9 <td class='test'><a class='test' href=...
# 10 <td class='test'>F</td>
# 11 None
# 12 <td class='test'>G</td>
# 13 <td class='test'><a class='test' href=...
# 14 <td class='test'>X</td>
推荐答案
您可以执行与以前相同的过程.
Your can do the same procedure as before.
唯一的警告是您必须在转换前执行not(〜)运算符.原因是该移位将在Series的第一个位置创建一个np.nan,这会将Series定义为float,从而导致not操作失败.
The only caveat is that you must do the not (~) operator before the shift. The reason is that the shift will create a np.nan in the first position of your Series, which will define the Series as floats, thus failing on the not operation.
import pandas as pd
import numpy as np
table = pd.Series(
["<td class='test'>AA</td>", # 0
"<td class='test'>A</td>", # 1
"<td class='test'><a class='test' href=...", # 2
"<td class='test'>B</td>", # 3
"<td class='test'><a class='test' href=...", # 4
"<td class='test'>BB</td>", # 5
"<td class='test'>C</td>", # 6
"<td class='test'><a class='test' href=...", # 7
"<td class='test'>F</td>", # 8
"<td class='test'>G</td>", # 9
"<td class='test'><a class='test' href=...", # 10
"<td class='test'>X</td>"]) # 11
not_contain = ~table.str.contains('href')
cond = not_contain & not_contain.shift(1)
array = np.insert(table.values, cond[cond].index, "None")
pd.Series(array)
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