TypeError:object()不带参数 [英] TypeError: object() takes no parameters

问题描述

我的代码生成以下错误:TypeError: object() takes no parameters

My code generates the following error: TypeError: object() takes no parameters

class Graph(object):
    def vertices(self):
        return list(self.__graph_dict.keys())

if __name__ == "__main__":

    g = { "a" : ["d"],
          "b" : ["c"],
          "c" : ["b", "c", "d", "e"],
          "d" : ["a", "c"],
          "e" : ["c"],
          "f" : []
        }

    graph = Graph(g)

    print("Vertices of graph:")
    print(graph.vertices())

有没有办法解决这个问题?

Is there a way I can solve this?

推荐答案

您的Graph类在__init__上不接受任何参数，因此在您调用时:

Your Graph class takes no arguments on __init__ therefore when you call:

图=图(g)

graph = Graph(g)

您收到一个错误，因为Graph不知道如何处理'g'. 我想您可能想要的是:

You get an error because Graph doesn't know what to do with 'g'. I think what you may want is:

class Graph(object):    
    def __init__(self, values):
        self.__graph_dict = values
    def vertices(self):
        return list(self.__graph_dict.keys())

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