Django异常中间件：TypeError：object（）不带参数 [英] Django exception middleware: TypeError: object() takes no parameters

问题描述

我正在使用Django 1.10，并尝试使用异常中间件捕获所有异常。

I'm using Django 1.10 and trying to catch all exceptions with exception middleware.

以下代码会导致内部服务器错误：

The code below causes an internal server error:

mw_instance = middleware(handler)
TypeError: object() takes no parameters

views.py

from django.http import HttpResponse

def my_view(request):
    x = 1/0 # cause an exception
    return HttpResponse("ok")

settings.py

settings.py

MIDDLEWARE = [
    'django.middleware.security.SecurityMiddleware',
    'django.contrib.sessions.middleware.SessionMiddleware',
    'django.middleware.common.CommonMiddleware',
    'django.middleware.csrf.CsrfViewMiddleware',
    'django.contrib.auth.middleware.AuthenticationMiddleware',
    'django.contrib.messages.middleware.MessageMiddleware',
    'django.middleware.clickjacking.XFrameOptionsMiddleware',
    'myproject.middleware.ExceptionMiddleware',  

]

middleware.py

middleware.py

from django.http import HttpResponse

class ExceptionMiddleware(object):
    def process_exception(self, request, exception): 
        return HttpResponse("in exception")

我有看到这些 object（）在Django 1.10中没有参数，并且还有其他关于中间件和Middleware_classes的问题，但是我不确定这对这种情况如何适用，或者我为解决该问题实际需要进行哪些更改。

I have seen these object() takes no parameters in django 1.10 and other questions talking about middleware versus middleware_classes, but I'm not sure how that applies to this case, or what I'd actually need to change to fix the issue.

推荐答案

由于您使用的是新的 MIDDLEWARE 设置，因此您的中间件类必须接受 get_response 参数： https：// docs.djangoproject.com/en/1.10/topics/http/middleware/#writing-your-own-middleware

Since you are using the new MIDDLEWARE settings, your Middleware class must accept a get_response argument: https://docs.djangoproject.com/en/1.10/topics/http/middleware/#writing-your-own-middleware

您可以这样编写课程：

from django.http import HttpResponse

class ExceptionMiddleware(object):
    def __init__(self, get_response):
        self.get_response = get_response

    def __call__(self, request):
        return self.get_response(request)

    def process_exception(self, request, exception): 
        return HttpResponse("in exception")

您还可以使用 MiddlewareMixin 使您的中间件与1.10之前和1.10之后的Django版本兼容： https://docs.djangoproject.com/en/1.10/topics/http / middleware /＃upgrading-pre-django-1-10-style-middleware

You could also use the MiddlewareMixin to make your Middleware compatible with pre-1.10 and post-1.10 Django versions: https://docs.djangoproject.com/en/1.10/topics/http/middleware/#upgrading-pre-django-1-10-style-middleware

from django.http import HttpResponse
from django.utils.deprecation import MiddlewareMixin

class ExceptionMiddleware(MiddlewareMixin):
    def process_exception(self, request, exception):
        return HttpResponse("in exception")

这篇关于Django异常中间件：TypeError：object（）不带参数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！