如何将记录传递给PL/pgSQL函数? [英] How to pass a record to a PL/pgSQL function?
问题描述
我有8个类似的PL/pgSQL函数;它们用作视图上的INSTEAD OF INSERT/UPDATE/DELETE
触发器以使其可写.每个视图都将一个通用表(在下面的示例中称为事物")和一个特殊表(在下面的"shape_things"和"flavored_things")的列组合在一起.顺便说一下,在我们的案例中,PostgreSQL的继承功能无法使用.
I have 8 similar PL/pgSQL functions; they are used as INSTEAD OF INSERT/UPDATE/DELETE
triggers on views to make them writable. The views each combine columns of one generic table (called "things" in the example below) and one special table ("shaped_things" and "flavored_things" below). PostgreSQL's inheritance feature can't be used in our case, by the way.
触发器必须在通用表中插入/更新行;这些部分在所有8个功能中都是相同的.由于通用表具有约30列,因此我试图在其中使用辅助函数,但是在将视图的NEW
记录传递给需要things
记录作为输入的函数时遇到了麻烦.
The triggers have to insert/update rows in the generic table; these parts are identical across all 8 functions. Since the generic table has ~30 columns, I'm trying to use a helper function there, but I'm having trouble passing the view's NEW
record to a function that needs a things
record as input.
(在此处和此处,但我没有认为我可以在我的情况下应用建议的解决方案.)
(Similar questions have been asked here and here, but I don't think I can apply the suggested solutions in my case.)
CREATE TABLE things (
id SERIAL PRIMARY KEY,
name TEXT NOT NULL
-- (plus 30 more columns)
);
CREATE TABLE flavored_things (
thing_id INT PRIMARY KEY REFERENCES things (id) ON DELETE CASCADE,
flavor TEXT NOT NULL
);
CREATE TABLE shaped_things (
thing_id INT PRIMARY KEY REFERENCES things (id) ON DELETE CASCADE,
shape TEXT NOT NULL
);
-- etc...
favoured_things的可写视图实现
CREATE VIEW flavored_view AS
SELECT t.*,
f.*
FROM things t
JOIN flavored_things f ON f.thing_id = t.id;
CREATE FUNCTION flavored_trig () RETURNS TRIGGER AS $fun$
DECLARE
inserted_id INT;
BEGIN
IF TG_OP = 'INSERT' THEN
INSERT INTO things VALUES ( -- (A)
DEFAULT,
NEW.name
-- (plus 30 more columns)
) RETURNING id INTO inserted_id;
INSERT INTO flavored_things VALUES (
inserted_id,
NEW.flavor
);
RETURN NEW;
ELSIF TG_OP = 'UPDATE' THEN
UPDATE things SET -- (B)
name = NEW.name
-- (plus 30 more columns)
WHERE id = OLD.id;
UPDATE flavored_things SET
flavor = NEW.flavor
WHERE thing_id = OLD.id;
RETURN NEW;
ELSIF TG_OP = 'DELETE' THEN
DELETE FROM flavored_things WHERE thing_id = OLD.id;
DELETE FROM things WHERE id = OLD.id;
RETURN OLD;
END IF;
END;
$fun$ LANGUAGE plpgsql;
CREATE TRIGGER write_flavored
INSTEAD OF INSERT OR UPDATE OR DELETE ON flavored_view
FOR EACH ROW EXECUTE PROCEDURE flavored_trig();
我想用帮助函数的调用替换上面标记为(A)"和(B)"的语句.
The statements marked "(A)" and "(B)" above are what I would like to replace with a call to a helper function.
我最初的尝试是将语句(A)"替换为
My initial attempt was to replace statement "(A)" with
inserted_id = insert_thing(NEW);
使用此功能
CREATE FUNCTION insert_thing (new_thing RECORD) RETURNS INTEGER AS $fun$
DECLARE
inserted_id INT;
BEGIN
INSERT INTO things (name) VALUES (
new_thing.name
-- (plus 30 more columns)
) RETURNING id INTO inserted_id;
RETURN inserted_id;
END;
$fun$ LANGUAGE plpgsql;
此操作失败,并显示错误消息"PL/pgSQL函数无法接受类型记录" .
This fails with the error message "PL/pgSQL functions cannot accept type record".
当调用函数insert_thing(NEW)
时,给参数类型things
无效:函数insert_thing(flavored_view)不存在"..
Giving the parameter the type things
doesn't work when the function is called as insert_thing(NEW)
: "function insert_thing(flavored_view) does not exist".
这里似乎不提供简单的转换; insert_thing(NEW::things)
产生无法将类型的flavored_view转换为事物" .为每个视图编写CAST函数将删除我们通过使用辅助函数获得的成果.
Simple casting doesn't seem to be available here; insert_thing(NEW::things)
produces "cannot cast type flavored_view to things". Writing a CAST function for each view would remove what we gained by using a helper function.
有什么想法吗?
推荐答案
有多种选择,具体取决于完整图片.
基本上,您的插入函数可以像这样工作:
There are various options, depending on the complete picture.
Basically, your insert function could work like this:
CREATE FUNCTION insert_thing (_thing flavored_view)
RETURNS int AS
$func$
INSERT INTO things (name) VALUES ($1.name) -- plus 30 more columns
RETURNING id;
$func$ LANGUAGE sql;
使用视图的行类型,因为触发器中的NEW
属于这种类型.
使用一个简单的SQL函数,该函数可以内联并且可能会更好.
Using the row type of the view, because NEW
in your trigger is of this type.
Use a simple SQL function, which can be inlined and might perform better.
演示呼叫:
SELECT insert_thing('(1, foo, 1, bar)');
在触发器内flavored_trig ()
:
inserted_id := insert_thing(NEW);
或者,基本上是重写的:
Or, basically rewritten:
IF TG_OP = 'INSERT' THEN
INSERT INTO flavored_things(thing_id, flavor)
VALUES (insert_thing(NEW), NEW.flavor);
RETURN NEW;
ELSIF ...
在PL/pgSQL之外不是有效的类型,它只是PL/pgSQL中未知行类型的通用占位符),因此您不能将其用于函数声明.record
is not a valid type outside PL/pgSQL, it's just a generic placeholder for a yet unknown row type in PL/pgSQL) so you cannot use it for an input parameter in a function declaration.record
For a more dynamic function accepting various row types you could use a polymorphic type. Examples:
- How to return a table by rowtype in PL/pgSQL
- Refactor a PL/pgSQL function to return the output of various SELECT queries
- How to write a function that returns text or integer values?
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