如何在Verilog中使用循环/生成来初始化参数化数组参数? [英] How to initialize parameterized array parameter using loop/generate in verilog?
问题描述
我要初始化一个参数化的数组参数,如下所示:
I want to initialize a parameterized array parameter as follow:
parameter n = 4;
parameter [(log2(n)-1):0] state [(n-1):0] = '{2'h3, 2'h2, 2'h1, 2'h0}; // for n=4
如果n = 4,则此分配工作正常.当n = 8时,它应初始化为
This assignment works fine if n=4. When n=8, it should initialize as
{3'h7, 3'h6, 3'h5, 3'h4, 3'h3, 3'h2, 3'h1, 3'h0}
我想这样初始化它:
for(i=0,i<n,i=i+1)
state[i] = i;
现在我应该用什么来进行初始化?我可以用generate来做吗? log2是一个函数.
Now what should I use to do this initialization? Can I do it with generate? Here log2 is a function.
推荐答案
首先,您正在使用SystemVerilog,它是Verilog的超级集合和后继者. Verilog不支持数组参数(矢量是可以的),并且Verilog无法分配整个未打包的数组('{}
是SystemVerilog).
First off, you are using SystemVerilog, the super-set and successor of Verilog. Verilog does not support arrayed parameters (vectors are okay) and Verilog cannot assign a whole unpacked array (the '{}
is SystemVerilog).
使用SystemVerilog,您可以使用以下方法自动缩放STATE
的值:
With SystemVerilog you can auto scale the values of STATE
with the following:
parameter N = 4;
parameter [(log2(N)-1):0] STATE [N] = state_val();
typedef [(log2(N)-1):0] state_t [N];
function state_t state_val();
for(int i=0; i<N; i++)
state_value[i] = i;
endfunction : state_val
注意:大多数编码风格指南建议对参数使用大写字母,对变量使用小写字母;这使得可读性更强.这就是为什么我在答案中将n
和state
更改为N
和STATE
的原因.
Note: Most coding style guidelines recommend using uppercase for parameters and lowercase for variables; this allows easier readability. This is why I changed n
and state
to N
and STATE
in my answer.
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