正则表达式返回两个特殊字符之间的所有字符 [英] Regular expression to return all characters between two special characters

问题描述

我将如何使用regx返回两个方括号之间的所有字符. 这是一个示例:

How would I go about using regx to return all characters between two brackets. Here is an example:

foobar['infoNeededHere']ddd
needs to return infoNeededHere

我发现一个正则表达式可以在花括号之间进行操作，但是所有尝试使其与方括号一起使用的尝试均失败了.这是该正则表达式:(?<={)[^}]*(?=})，这是我尝试对其进行破解

I found a regex to do it between curly brackets but all attempts at making it work with square brackets have failed. Here is that regex: (?<={)[^}]*(?=}) and here is my attempt to hack it

(?<=[)[^}]*(?=])

最终解决方案:

import re

str = "foobar['InfoNeeded'],"
match = re.match(r"^.*\['(.*)'\].*$",str)
print match.group(1)

推荐答案

^.*\['(.*)'\].*$ 将与排成一行并捕获您想要的东西.

^.*\['(.*)'\].*$ will match a line and capture what you want in a group.

您必须使用\

rubular.com 证明链接上的文档将解释表达式的形成方式.

The documentation at the rubular.com proof link will explain how the expression is formed.

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