正则表达式以任意顺序匹配至少两个特殊字符 [英] Regular expression to match at least two special characters in any order

问题描述

我必须对密码进行jQuery表单验证.

I have to do jQuery form validation for password.

密码应至少包含两个任意顺序的特殊字符.我尝试过 用于密码验证的正则表达式，但是它不能解决两个随机的特殊字符会出现的问题任何订单.

The password should contain at least two special characters in any order. I have tried with Regular Expression for password validation but it does not address that two random special characters can come at any order.

如何使用JavaScript正则表达式来做到这一点?

How do I do it using a JavaScript regular expression?

推荐答案

在不必要的情况下，您不必使用环视.

You do not have to use look-arounds in cases when you do not have to.

如果只需要确保字符串中至少包含2个特定集合的字符，请使用这种正则表达式(使用否定的类使其更健壮):

If you only need to make sure the string has at least 2 characters of a specific set, use this kind of a regex (with a negated class to make it more robust):

/(?:[^`!@#$%^&*\-_=+'\/.,]*[`!@#$%^&*\-_=+'\/.,]){2}/

请参见演示

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