Python，如何将字符串解析为sys.argv [英] Python, how to parse strings to look like sys.argv

问题描述

我想解析这样的字符串:

I would like to parse a string like this:

-o 1  --long "Some long string"  

对此:

["-o", "1", "--long", 'Some long string']

或类似的

这与getopt或optparse不同，后者以sys.argv解析的输入(例如我上面的输出)以 start 开始.有没有标准的方法可以做到这一点?基本上，这是拆分"，同时将引用的字符串保持在一起.

This is different than either getopt, or optparse, which start with sys.argv parsed input (like the output I have above). Is there a standard way to do this? Basically, this is "splitting" while keeping quoted strings together.

到目前为止，我最好的功能:

My best function so far:

import csv
def split_quote(string,quotechar='"'):
    '''

    >>> split_quote('--blah "Some argument" here')
    ['--blah', 'Some argument', 'here']

    >>> split_quote("--blah 'Some argument' here", quotechar="'")
    ['--blah', 'Some argument', 'here']
    '''
    s = csv.StringIO(string)
    C = csv.reader(s, delimiter=" ",quotechar=quotechar)
    return list(C)[0]

推荐答案

我相信您想要 shlex 模块.

>>> import shlex
>>> shlex.split('-o 1 --long "Some long string"')
['-o', '1', '--long', 'Some long string']

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