DateTimeFormatter中的通配符 [英] Wildcard in DateTimeFormatter

问题描述

我需要将字符串解析为LocalDate.该字符串看起来像用正则表达式表示的31.* 03 2016(即.*表示在日期号之后可能有0个或更多的未知字符).

I need to parse a string into a LocalDate. The string looks like 31.* 03 2016 in regex terms (i.e. .* means that there may be 0 or more unknown characters after the day number).

示例输入/输出:31xy 03 2016 ==> 2016-03-31

Example input/output: 31xy 03 2016 ==> 2016-03-31

我希望在DateTimeFormatter文档中找到通配符语法，以允许使用以下模式:

I was hoping to find a wildcard syntax in the DateTimeFormatter documentation to allow a pattern such as:

LocalDate.parse("31xy 03 2016", DateTimeFormatter.ofPattern("dd[.*] MM yyyy"));

但是我什么也找不到.

是否有一种简单的方法来用DateTimeFormatter表示可选的未知字符?

Is there a simple way to express optional unknown characters with a DateTimeFormatter?

ps:我显然可以在解析字符串之前对其进行修改，但这不是我要的.

ps: I can obviously modify the string before parsing it but that's not what I'm asking for.

推荐答案

java.time中没有对此的直接支持.

There is no direct support for this in java.time.

最接近的方法是使用

虽然以上内容未经测试，但基本上可以正常工作.但是，手动解析会容易得多.

While the above is untested it should basically work. However, it would be far easier parse it manually.

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