在Python中更改字符时拆分 [英] Split when character changes in Python

问题描述

所以我有这个字符串.

6#666#665533999

我想将其解析为多个小字符串(或直到字符更改)，然后忽略#，以便像电话的拨号盘一样替换6 = M or 666 = O or 9 = W.

And I want to parse it into multiple small strings(or until the character changes) and ignoring the # so that I can substitute 6 = M or 666 = O or 9 = W just like a phone's dial pad.

6#666#665533999 -> 6, 666, 66, 55, 33, 999

所以我用split('#')方法删除了#并且不知道下一步该怎么做.对此吗?

So I used the split('#') method to remove the # and can't figure out what to do next.I have tried brute force methods which solves it to a certain extent but is there an easier or more elegant solution to this?

推荐答案

使用 itertools.groupby :

>>> c = "6#666#665533999"
>>> ["".join(g) for k, g in groupby(c) if k != '#']
['6', '666', '66', '55', '33', '999']

然后有一个字典，将这些集合中的每一个映射到拨号盘中的一个字符.

Then have a dictionary which maps each of these sets to a character in the dial pad.

cmap = {'77': 'Q', '9999': 'Z'} # And so forth..

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