在python字符串中拆分字母和数字字符的快速方法 [英] Fast way to split alpha and numeric chars in a python string

问题描述

我正在尝试制定一个简单的函数来捕获拼写错误，例如:

Westminister15"Westminister15London"23Westminister15London"

固定后:

["Westminister", "15"][威斯敏斯特"、15"、伦敦"][23"、威斯敏斯特"、15"、伦敦"]

第一次尝试:

 def fixate(query):digit_pattern = re.compile(r'\D')alpha_pattern = re.compile(r'\d')数字 = 过滤器(无，digit_pattern.split(查询))alphas = filter(None, alpha_pattern.split(query))打印数字打印阿尔法

结果:

 fixate("Westminister15London")>['15']>['威斯敏斯特'，'伦敦']

但是，我认为这可以更有效地完成，但当我尝试以下操作时仍然会得到糟糕的结果:

 fixate("Westminister15London England")>['15']>['威斯敏斯特'、'伦敦英格兰']

显然它应该分别使用 London 和 England，但我觉得我的函数会被过度修补，有一个更简单的方法

这个问题有点等价于这个 php 问题

解决方案

问题在于 Python 的 re.split() 不会在零长度匹配时进行拆分.但是你可以用 re.findall() 得到想要的结果:

<预><代码>>>>re.findall(r"[^\W\d_]+|\d+", "23Westminister15London")['23'、'威斯敏斯特'、'15'、'伦敦']>>>re.findall(r"[^\W\d_]+|\d+", "Westminister15London England")['威斯敏斯特'、'15'、'伦敦'、'英格兰']

\d+ 匹配任意数量的数字，[^\W\d_]+ 匹配任意单词.

I am trying to work out a simple function to capture typos, e.g:

"Westminister15"
"Westminister15London"
"23Westminister15London"

after fixating:

["Westminister", "15"]
["Westminister", "15", "London"]
["23", "Westminister", "15", "London"]

First attempt:

 def fixate(query):
     digit_pattern = re.compile(r'\D')
     alpha_pattern = re.compile(r'\d')
     digits = filter(None, digit_pattern.split(query))
     alphas = filter(None, alpha_pattern.split(query))
     print digits
     print alphas

result:

 fixate("Westminister15London")

 > ['15']
 > ['Westminister', 'London']

However, I think this could be done more effectively, and I still get bad results when I try something like:

 fixate("Westminister15London England")

 > ['15']
 > ['Westminister', 'London England']

Obviously it should enlist London and England separately, but I feel my function will get overly patched and theres a simpler approach

This question is somewhat equivalent to this php question

解决方案

The problem is that Python's re.split() doesn't split on zero-length matches. But you can get the desired result with re.findall():

>>> re.findall(r"[^\W\d_]+|\d+", "23Westminister15London")
['23', 'Westminister', '15', 'London']
>>> re.findall(r"[^\W\d_]+|\d+", "Westminister15London England")
['Westminister', '15', 'London', 'England']

\d+ matches any number of digits, [^\W\d_]+ matches any word.

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