排序的字母数字字符串降序 [英] Sort Alphanumeric String Descending

问题描述

我需要如下排序​​字母数字项目的数组。发件人：

I need to sort an array of alphanumerical items as follows. From:

2 xxx
20 axxx
38 xxxx
20 bx
8540 xxxxxx

到

8540 xxxxx
38 xxxx
20 axxx
20 bx
2 xxx

因此​​，分类就下降到了号，然后按字母顺序上升。数字总是从字母字符分隔（记为XXXX），由一个单一的空间，但数量也变长。

Thus, sorted descending with respect to the numbers, then ascending alphabetically. The numbers are always separated from the alphabetical characters (denoted "xxxx") by a single space, but the numbers are variable length.

我怀疑我需要使用正则表达式的一些由空间，然后排序它sort（）函数和分裂出的数字，但我不知道如何在字母排序领带。任何code样？非常感谢！

I suspect I need to use some Regex in the sort() function and splitting off the numbers by the space then sorting it, but I don't know how to tie in the alphabetical sorting. Any code samples? Thanks so much!

推荐答案

无需正则表达式，因为<一href=\"https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/sort\"><$c$c>Array.sort()接受自定义函数：

No need for RegEx, because Array.sort() accepts custom function:

http://jsfiddle.net/EFGK9/

var arr=["2 xxx","20 axxx","38 xxxx","20 bx","8540 xxxxxx"];
arr.sort(function(a,b){
    a=a.split(" ");
    b=b.split(" ");
    var an=parseInt(a[0],10);
    var bn=parseInt(b[0],10);
    return an<bn?1:(an>bn?-1:(a[1]<b[1]?-1:(a[1]>b[1]?1:0)));
});
console.log(arr);

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