排序字母数字字符串java [英] Sorting alphanumeric strings java
问题描述
我有这个数组存储用户添加的一些URL的后缀:
I have this array storing the suffix of some URLs the user is adding:
[U2, U3, U1, U5, U8, U4, U7, U6]
当我这样做时:
for (Map<String, String> map : getUrlAttachments()) {
String tmpId = map.get("id"); //it receives the U2, in the 1st iteration, then U3, then U1,...
if (tmpId.charAt(0) == 'U') {
tmpId.charAt(1);//2, then 3, then 1,...
String url = map.get("url");
String description = map.get("description");
URLAttachment attachment;
String cleanup = map.get("cleanup");
if (cleanup == null && url != null && description != null) {
attachment = new URLAttachmentImpl();
attachment.setOwnerClass(FileUploadOwnerClass.Event.toString());
attachment.setUrl(url);
attachment.setDescription(description);
attachment.setOwnerId(auctionHeaderID);
attachment.setUrlAttachmentType(URLAttachmentTypeEnum.EVENT_ATTACHMENT);
attachment.setDateAdded(new Date());
urlBPO.save(attachment);
}
我的问题:
我想更改此 For
条件,方法是传递另一个列表,映射排序的数据,如 [U1 ,U2,U3,U4,U5,U6,U7,U8]
。
I want to change this For
condition by passing another list mapping the data sorted like [U1, U2, U3, U4, U5, U6, U7, U8]
.
我希望你的帮助知道什么是最好的方法我可以这样做。
I'd like your help to know what's the best way I could do this.
我想创建一个列出id的数组,然后排序,但我不知道如何在java中对字母数字字符串进行排序。
I thought about creating an array listing the ids and then sort then, but I don't know how exactly to sort alphanumeric strings in java.
推荐答案
我决定使用@Abu给出的想法,但我改编了它:
I decide to use the idea @Abu gave, but I adapted it:
- 我检查用户试图添加的网址的ID,
- 我删除了此ID中的字母后缀,然后创建了一个
ArrayList
用于存储每个id的数字部分。 -
我对此排序
ArrayList
喜欢@Abu在他的答案中教我,然后我按顺序验证这个排序的ArrayList
中的每个id应该添加..
- I check the ids of the urls the user is trying to add,
- I remove the alphabetic suffix in this id and then I create an
ArrayList
to store the numerical part of each id. I sort this
ArrayList
like @Abu taught me in his answer and then I verify for each id in this sortedArrayList
in the sequence it should be added..
ArrayList <Integer> urlSorted = new ArrayList<Integer>();
//sort the url ids
for (Map<String, String> map : getUrlAttachments()) {
String tmpId = map.get("id");
if (tmpId.charAt(0) == 'U') {
//gets the id, removing the prefix 'U'
urlSorted.add( Integer.valueOf(tmpId.substring(1)));
}
}
//sort the urlIds to check the sequence they must be added
Collections.sort(urlSorted);
//checks for each url id, compares if it's on the natural order of sorting to be added.
for(Integer urlId: urlSorted) {
for (Map<String, String> map : getUrlAttachments()) {
String sortedId = "U"+urlId;
String tmpId = map.get("id");
//compare the ids to add the 1, then 2, then 3...
if (map.get("id").equals(sortedId)) {
//code to save according to the sorted ids.
}
}
}
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