在php中生成随机密码 [英] Generating a random password in php

问题描述

我正在尝试在php中生成一个随机密码.

I am trying to generate a random password in php.

但是我得到的都是'a'，返回类型是array类型，我希望它是一个字符串.有关如何更正代码的任何想法?

However I am getting all 'a's and the return type is of type array and I would like it to be a string. Any ideas on how to correct the code?

谢谢.

function randomPassword() {
    $alphabet = "abcdefghijklmnopqrstuwxyzABCDEFGHIJKLMNOPQRSTUWXYZ0123456789";
    for ($i = 0; $i < 8; $i++) {
        $n = rand(0, count($alphabet)-1);
        $pass[$i] = $alphabet[$n];
    }
    return $pass;
}

推荐答案

安全警告:rand()不是密码安全的伪随机数生成器.在其他地方查找在PHP中生成加密安全的伪随机字符串.

Security warning: rand() is not a cryptographically secure pseudorandom number generator. Look elsewhere for generating a cryptographically secure pseudorandom string in PHP.

尝试一下(使用strlen而不是count，因为字符串上的count始终是1):

Try this (use strlen instead of count, because count on a string is always 1):

function randomPassword() {
    $alphabet = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890';
    $pass = array(); //remember to declare $pass as an array
    $alphaLength = strlen($alphabet) - 1; //put the length -1 in cache
    for ($i = 0; $i < 8; $i++) {
        $n = rand(0, $alphaLength);
        $pass[] = $alphabet[$n];
    }
    return implode($pass); //turn the array into a string
}

演示: http://codepad.org/UL8k4aYK

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