PHP中的随机密码生成器未返回密码 [英] Random password generator in PHP not returning password
本文介绍了PHP中的随机密码生成器未返回密码的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试在php中设置随机密码生成器功能,但这对我不起作用.我收到错误消息:
I am trying to set up a random password generator function in php but this is not working for me. I get the error:
注意:第12行的C:\ xampp \ htdocs \ php-testing \ index.php中的数组到字符串的转换
Notice: Array to string conversion in C:\xampp\htdocs\php-testing\index.php on line 12
数组
我在做什么错了?
<?php
function pwGenerator($len = 10) {
$charRange = "abcdefghijklmnopqrstuwxyzABCDEFGHIJKLMNOPQRSTUWXYZ0123456789!@#$%^&*()";
$pw = array();
$length = strlen($charRange);
for ($x = 0; $x < $len; $x++) {
$n = rand(0, $length);
$pw[] = $charRange[$n];
}
return $pw;
}
echo pwGenerator();
推荐答案
您不能直接将数组转换为字符串.因此,可以将字符附加在字符串中,而不是将其存储在数组中.现在它正在工作.
You cannot convert array into string directly. So instead of storing it in array you can attach characters with a string. and now it is working.
<?php
function pwGenerator($len = 10) {
$charRange = "abcdefghijklmnopqrstuwxyzABCDEFGHIJKLMNOPQRSTUWXYZ0123456789!@#$%^&*()";
$pw = null;
$length = strlen($charRange);
for ($x = 0; $x < $len; $x++) {
$n = rand(0, $length);
$pw .= $charRange[$n];
}
return $pw;
}
echo pwGenerator();
?>
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