如何将子目录递归添加到PATH? [英] How to recursively add subdirectories to the PATH?

问题描述

您如何做到的?我的目录code/在工作中，被组织在文件夹，子文件夹和子文件夹中，所有这些文件夹(至少从理论上来说)都包含我要定期运行的脚本或程序.

How do you do it? My directory code/, at work, is organized in folders and subfolders and subsubfolders, all of which (at least in theory) contain scripts or programs I want to run on a regular basis.

推荐答案

在脚本的末尾添加以下行:

At the end of your script, put the line:

PATH=${PATH}:$(find ~/code -type d | tr '\n' ':' | sed 's/:$//')

这会将〜/代码树中的每个目录追加到当前路径.我自己不喜欢这个主意，宁愿只有几个目录保存我自己的可执行文件并显式列出它们，但每个目录都属于自己.

This will append every directory in your ~/code tree to the current path. I don't like the idea myself, preferring to have only a couple of directories holding my own executables and explicitly listing them, but to each their own.

如果要排除所有隐藏目录，则基本上需要删除具有序列"/."的每一行(以确保您也不会检查隐藏目录下的子目录):

If you want to exclude all directories which are hidden, you basically need to strip out every line that has the sequence "/." (to ensure that you don't check subdirectories under hidden directories as well):

PATH=${PATH}:$(find ~/code -type d | sed '/\/\\./d' | tr '\n' ':' | sed 's/:$//')

这将阻止您获取诸如~/code/level1/.hidden/level3/之类的目录(即，一旦检测到它们被隐藏，它将停止在子树中搜索).如果您只想保留隐藏目录，但仍允许在其下放置非隐藏目录，请使用:

This will stop you from getting directories such as ~/code/level1/.hidden/level3/ (i.e., it stops searching within sub-trees as soon as it detects they're hidden). If you only want to keep the hidden directories out, but still allow non-hidden directories under them, use:

PATH=${PATH}:$(find ~/code -type d -name '[^\.]*' | tr '\n' ':' | sed 's/:$//')

这将允许~/code/level1/.hidden2/level3/，但不允许~/code/level1/.hidden2/.hidden3/，因为-name仅检查文件的基本名称，而不检查完整路径名.

This would allow ~/code/level1/.hidden2/level3/ but disallow ~/code/level1/.hidden2/.hidden3/ since -name only checks the base name of the file, not the full path name.

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