击：递归子目录添加到路径 [英] Bash: Recursively adding subdirectories to the path

问题描述

你是怎么做到的呢？我的code /在工作目录中的文件夹和子文件夹和subsubfolders，所有这一切（至少在理论上）包含我想定期运行的脚本或程序组织。

How do you do it? My code/ directory at work is organized in folders and subfolders and subsubfolders, all of which (at least in theory) contain scripts or programs I want to run on a regular basis.

它的转向我，否则风景如画的.bashrc到碍眼！

Its turning my otherwise picturesque .bashrc into an eyesore!

谢谢！

推荐答案

在你的脚本的末尾，放线：

At the end of your script, put the line:

PATH=${PATH}:$(find ~/code -type d | tr '\n' ':' | sed 's/:$//')

这会在你的〜/ code树的每个目录附加到当前路径。我不喜欢这个主意我自己，preferring有只有一对夫妇的目录举行自己的可执行文件，并明确列出了他们，但每一个自己。

This will append every directory in your ~/code tree to the current path. I don't like the idea myself, preferring to have only a couple of directories holding my own executables and explicitly listing them, but to each their own.

如果您想排除这是隐藏的所有目录，你基本上需要去掉每一个具有序列行/。（确保你不' t检查子目录下隐藏的目录以及）：

If you want to exclude all directories which are hidden, you basically need to strip out every line that has the sequence "/." (to ensure that you don't check subdirectories under hidden directories as well):

PATH=${PATH}:$(find ~/code -type d | sed '/\/\\./d' | tr '\n' ':' | sed 's/:$//')

这会阻止你从得到的目录，如〜/ code / 1级/ .hidden / 3级/ （即，它停止子树作为搜索范围内只要发现他们是隐藏的）。如果你只是想保持隐藏的目录出来，但仍然允许非隐藏目录下他们使用：

This will stop you from getting directories such as ~/code/level1/.hidden/level3/ (i.e., it stops searching within sub-trees as soon as it detects they're hidden). If you only want to keep the hidden directories out, but still allow non-hidden directories under them, use:

PATH=${PATH}:$(find ~/code -type d -name '[^\.]*' | tr '\n' ':' | sed 's/:$//')

这将允许〜/ code / 1级/ .hidden2 / 3级/ 但不允许〜/ code / 1级/ .hidden2 / .hidden3 / ，因为 -name 只检查文件的基本名称，而不是全路径名。

This would allow ~/code/level1/.hidden2/level3/ but disallow ~/code/level1/.hidden2/.hidden3/ since -name only checks the base name of the file, not the full path name.

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