如何在VBScript中获取文件的标准路径? [英] How to get the fully qualified path for a file in VBScript?

问题描述

我正在使用Shell.Application对象，该对象允许我编写zip文件的脚本.

I am using the Shell.Application object, which allows me to script creation of a zip file.

但是为了使其正常工作，我需要zip文件的完整路径. File.zip不起作用.即使脚本在找到文件的相同目录中运行，我也需要c:\the\full\path\file.zip.

But in order for this to work, I need to full path of the zip file. File.zip doesn't work. I need c:\the\full\path\file.zip, even if the script is running within the same directory where the file is found.

如何在 VBScript 中获取文件的完整路径?

How can I get the full path of a file in VBScript?

类似cmd.exe Shell中的%~fI扩展.

Something like the %~fI expansion in the cmd.exe shell.

推荐答案

在 Scripting.FileSystemObject ，有一种叫做

On Scripting.FileSystemObject, there's a method called GetAbsolutePathName that does this.

这对我有用:

Dim folderName
folderName = "..\.."

Dim fso
Set fso = CreateObject("Scripting.FileSystemObject")

Dim fullpath
fullpath = fso.GetAbsolutePathName(folderName)

WScript.Echo "folder spec: " & folderName
WScript.Echo "fullpath:    " & fullpath

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