itertools产品生成所有可能的大小为3的字符串 [英] itertools product to generate all possible strings of size 3
问题描述
输入:
pos_1= 'AVNMHDRW'
pos_2= 'KNTHDYBW'
pos_3= 'KVNGSDRB'
尝试使用pos_1中的一项,pos_2中的一项以及pos_3中的一项来查找所有可能的三元组
Trying to find all possible triplets using one item from pos_1, one from pos_2, and one from pos_3
我试图弄清楚如何使用itertools.product(*),但我有些困惑
I'm trying to figure out how to use itertools.product(*) but I'm a little confused
最终,我想通过从pos_1中获取一个,然后从pos_2中获取一个,再从pos_3中获取一个,来创建所有不同可能性的列表(或生成器对象)
Ultimately, I want to create a list (or generator object) of all the different possibilities by taking one from pos_1 then one from pos_2 and then one from pos_3
示例输出:
'AKK','ANV','WWB'
pos_1代表位置1,以此类推代表pos_2和pos_3.
pos_1 stands for position one and so on for pos_2 and pos_3.
推荐答案
简单:
itertools.product(pos_1, pos_2, pos_3)
这可以反复进行;如果需要列表,只需将其传递给list
.
This can be iterated over; if you want a list, just pass it to list
.
到底是什么问题?
这将生成每个源中项目的元组.如果您想将它们重新连接成字符串,则可以在进行迭代时手动执行以下操作:
This produces tuples of the items from each source. If you want to join them back into strings, you can do that manually when you iterate:
for a, b, c in itertools.product(pos_1, pos_2, pos_3):
do_something_with(a + b + c)
或创建列表,您可以使用列表理解:
or to create the list, you can use a list comprehension:
[a + b + c for a, b, c in itertools.product(pos_1, pos_2, pos_3)]
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