SimpleXML:选择具有特定属性值的元素 [英] SimpleXML: Selecting Elements Which Have A Certain Attribute Value

问题描述

在XML文档中，我具有共享相同名称的元素，但是属性的值定义了它是什么类型的数据，并且我想从文档中选择所有具有特定值的元素.我是否需要使用XPath(如果可以，建议使用正确的语法)还是有一个更优雅的解决方案?

In an XML document, I have elements which share the same name, but the value of an attribute defines what type of data it is, and I want to select all of those elements which have a certain value from the document. Do I need to use XPath (and if so, could you suggest the right syntax) or is there a more elegant solution?

以下是一些XML示例:

Here's some example XML:

<object>
  <data type="me">myname</data>
  <data type="you">yourname</data>
  <data type="me">myothername</data>
</object>

我想选择类型为me的所有<data>标记子级<object>的内容.

And I want to select the contents of all <data> tags children of <object> who's type is me.

PS-我正在尝试使用PHP与Netflix API进行接口-这与我的问题无关紧要，但是如果您想提出一种更好的方法，我会全力以赴.

PS - I'm trying to interface with the Netflix API using PHP - this shouldn't matter for my question, but if you want to suggest a good/better way to do so, I'm all ears.

推荐答案

尝试使用此XPath:

Try this XPath:

/object/data[@type="me"]

所以:

$myDataObjects = $simplexml->xpath('/object/data[@type="me"]');

如果object不是文档的根目录，请改用//object/data[@type="me"].

And if object is not the root of your document, use //object/data[@type="me"] instead.

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