如何获取具有特定属性值的特定XML元素? [英] How to get specific XML elements with specific attribute value?
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问题描述
我试图通过获取所有< Type>
元素来解析URL中的XML文件,其中参数type_id =4218??
I am trying to parse an XML file from a URL by taking all "<Type>
" elements where is parameter type_id="4218"??
XML文档:
<BSQCUBS Version="0.04" Date="Fri Dec 9 11:43:29 GMT 2011" MachineDate="Fri, 09 Dec 2011 11:43:29 +0000">
<Class class_id="385">
<Title>Football Matches</Title>
<Type type_id="4264" type_minbet="0.1" type_maxbet="2000.0">
...
</Type>
<Type type_id="5873" type_minbet="0" type_maxbet="0">
...
</Type>
<Type type_id="4725" type_minbet="0.1" type_maxbet="2000.0">
...
</Type>
<Type type_id="4218" type_minbet="0.1" type_maxbet="2000.0">
...
</Type>
<Type type_id="4221" type_minbet="0.1" type_maxbet="2000.0">
...
</Type>
<Type type_id="4218" type_minbet="0.1" type_maxbet="2000.0">
...
</Type>
<Type type_id="4299" type_minbet="0.1" type_maxbet="2000.0">
...
</Type>
</Class>
</BSQCUBS>
这是我的Java代码:
Here is my Java code:
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(new URL("http://cubs.bluesq.com/cubs/cubs.php?action=getpage&thepage=385.xml").openStream());
doc.getDocumentElement().normalize();
NodeList nodeList = doc.getElementsByTagName("Type");
System.out.println("ukupno:"+nodeList.getLength());
if (nodeList != null && nodeList.getLength() > 0) {
for (int j = 0; j < nodeList.getLength(); j++) {
Element el = (org.w3c.dom.Element) nodeList.item(j);
type_id = Integer.parseInt(el.getAttribute("type_id"));
System.out.println("type id:"+type_id);
}
}
这段代码给了我所有元素,我不知道想要那个,我想要属性type_id =4218的所有元素!
This code gives me all elements, I don't want that, I want all elements where the attribute type_id = "4218"!
推荐答案
XPath是你的正确选择:
XPath is right choice for you:
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse("<Your xml doc uri>");
XPathFactory xPathfactory = XPathFactory.newInstance();
XPath xpath = xPathfactory.newXPath();
XPathExpression expr = xpath.compile("//Type[@type_id=\"4218\"]");
NodeList nl = (NodeList) expr.evaluate(doc, XPathConstants.NODESET);
并遍历 nl
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