从HTML标记中删除样式属性 [英] Remove style attribute from HTML tags

问题描述

我对正则表达式不太满意，但是对于PHP，我想从TinyMCE返回的字符串中的HTML标记中删除style属性.

I'm not too good with regular expressions, but with PHP I'm wanting to remove the style attribute from HTML tags in a string that's coming back from TinyMCE.

因此将<p style="...">Text</p>更改为仅香草<p>Test</p>.

我该如何使用preg_replace()函数来实现此目的?

How would I achieve this with something like the preg_replace() function?

推荐答案

实用的正则表达式(<[^>]+) style=".*?"将在所有合理的情况下解决此问题.不是第一个捕获组的匹配部分应被删除，像这样:

The pragmatic regex (<[^>]+) style=".*?" will solve this problem in all reasonable cases. The part of the match that is not the first captured group should be removed, like this:

$output = preg_replace('/(<[^>]+) style=".*?"/i', '$1', $input);

匹配一个<，然后匹配一个或多个"not >"，直到我们进入space和style="..."部分. /i使它甚至可以与STYLE="..."一起使用.用捕获的组$1替换此匹配项.如果标签不包含style="..."，则会保留该标签.

Match a < followed by one or more "not >" until we come to space and the the style="..." part. The /i makes it work even with STYLE="...". Replace this match with $1, which is the captured group. It will leave the tag as is, if the tag doesn't include style="...".

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