使用MySQLi和PHP的HTML表 [英] HTML table using MySQLi and PHP

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本文介绍了使用MySQLi和PHP的HTML表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试将一个表连接到我的数据库,以便可以使用该数据库中的信息.

I'm trying to make a table connected to my database so I can use the information in that database.

我认为我的方法正确,但是目前该表仅显示第一行.任何人都对发生的事情有任何想法吗?

I think I'm on the right way, but currently the table only displays the first row. Anyone got any ideas on what's going on?

         <table id="fairtable">
            <tr>
                <td>Fair Name</td>
                <td>Date</td>
                <td>Are we there?</td>
                <td>Website</td>
            </tr>
            <?php 
            $sql = "SELECT `name`,`date`,`present`,`website` FROM `dates`";
            $results = mysqli_query($conn,$sql);

            while($rowitem = mysqli_fetch_array($results)) {
            echo "<tr>";
                echo "<td>" . $rowitem['name'] . "</td>";
                echo "<td>" . $rowitem['date'] . "</td>";
                echo "<td>" . $rowitem['present'] . "</td>";
                echo "<td>" . $rowitem['website'] . "</td>";
            echo "</tr>";
            }
            ?>
        </table>

推荐答案

这也许是因为您没有正确打开HTML表标签,这很容易忽略.还可以在白色语句中循环结果集:

Perhaps this is because you have not opened your HTML table tags correctly, its an easy thing to overlook. Also loop the result set inside a white statement:

$sql = "SELECT `name`,`date`,`present`,`website` FROM `dates`";
$results = mysqli_query($conn,$sql);
echo "<table>"; //begin table tag...
//you can add thead tag here if you want your table to have column headers
 while($rowitem = mysqli_fetch_array($results)) {
    echo "<tr>";
    echo "<td>" . $rowitem['name'] . "</td>";
    echo "<td>" . $rowitem['date'] . "</td>";
    echo "<td>" . $rowitem['present'] . "</td>";
    echo "<td>" . $rowitem['website'] . "</td>";*/
    echo "</tr>";
}
echo "</table>"; //end table tag

这篇关于使用MySQLi和PHP的HTML表的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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