如何使用 php 和 sql 连接 html 风格化表 [英] How to concatenate html stylized table with php and sql

问题描述

所以，我有这个代码返回一个带有正确数据库值的简单表:

<tr><th>Código</th><th>Nome</th><th>Indicou</th></tr>";而($coluna_bd_tabela = mysqli_fetch_array($sql_indicador_resul)){echo "";回声<td>".$coluna_bd_tabela['usu_codigo'] ."</td>";回声<td>".$coluna_bd_tabela['usu_nome'] ."</td>";回声<td>".$coluna_bd_tabela['usu_indicador_codigo'] ."</td>";回声</tr>";}echo "</table>";?>

这是没有查询工作的风格化表格:

<头><tr><th style="width: 1%">#</th><th style="width: 20%">Nome</th><th>最近的成员</th><th>项目进展</th><th>状态</th><th style="width: 20%">#Edit</th></tr></thead><tr><td>echo $coluna_bd_tabela['usu_codigo']</td><td><a>echo $coluna_bd_tabela['usu_nome']<br/><small>echo $coluna_bd_tabela['usu_indicou']</small></td><td><ul class="list-inline"><li><img src="images/user.png" class="avatar" alt="Avatar"><li><img src="images/user.png" class="avatar" alt="Avatar"><li><img src="images/user.png" class="avatar" alt="Avatar"><li><img src="images/user.png" class="avatar" alt="Avatar"></td><td class="project_progress"><div class="progress progress_sm"><div class="progress-bar bg-green" role="progressbar" data-transitiongoal="57"></div>
<small>57% 完成</small></td><td><button type="button" class="btn btn-success btn-xs">成功</button></td><td><a href="#" class="btn btn-primary btn-xs"><i class="fa fa-folder"></i>查看<a href="#" class="btn btn-info btn-xs"><i class="fa fa-pencil"></i>编辑<a href="#" class="btn btn-danger btn-xs"><i class="fa fa-trash-o"></i>删除</td></tr></tbody>
我想显示带有查询值的风格化表格，但这毁了我.数据库连接很好，这些是对包含连接的查询，它们也工作正常，如简单表所示:
$sql_indicador = "SELECT * FROM esc_usuarios WHERE usu_indicador_codigo = '" .$_SESSION['codigo'] ."'";$sql_indicador_resul = mysqli_query($conexao, $sql_indicador);
解决方案
提供完整的解决方案:
<头><tr><th style="width: 1%">#</th><th style="width: 20%">Nome</th><th>最近的成员</th><th>项目进展</th><th>状态</th><th style="width: 20%">#Edit</th></tr></thead><?php while($coluna_bd_tabela = mysqli_fetch_array($sql_indicador_resul)){ ?><tr><td><?php echo $coluna_bd_tabela['usu_codigo'];?></td><td><a><?php echo $coluna_bd_tabela['usu_nome'];?></a><br/><small><?php echo $coluna_bd_tabela['usu_indicou'];?></小></td><td><ul class="list-inline"><li><img src="images/user.png" class="avatar" alt="Avatar"><li><img src="images/user.png" class="avatar" alt="Avatar"><li><img src="images/user.png" class="avatar" alt="Avatar"><li><img src="images/user.png" class="avatar" alt="Avatar"></td><td class="project_progress"><div class="progress progress_sm"><div class="progress-bar bg-green" role="progressbar" data-transitiongoal="57"></div>
<small>57% 完成</small></td><td><button type="button" class="btn btn-success btn-xs">成功</button></td><td><a href="#" class="btn btn-primary btn-xs"><i class="fa fa-folder"></i>查看<a href="#" class="btn btn-info btn-xs"><i class="fa fa-pencil"></i>编辑<a href="#" class="btn btn-danger btn-xs"><i class="fa fa-trash-o"></i>删除</td></tr></tbody><?php } ?>

您忘记在 echo 语句周围使用 <?php 和 ?> 开始和结束标记.此外，您错过了每个语句末尾的 ;.我还将表格的开头和结尾移出了 PHP 的 echo，因为我相信这样看起来更清晰.

So, i have this code that returns me a simple table with the correct db values:

<?php
    echo "<table border='1'>
          <tr>
            <th>Código</th>
            <th>Nome</th>
            <th>Indicou</th>
          </tr>";

    while($coluna_bd_tabela = mysqli_fetch_array($sql_indicador_resul)){
        echo "<tr>";
        echo "<td>" . $coluna_bd_tabela['usu_codigo'] . "</td>";
        echo "<td>" . $coluna_bd_tabela['usu_nome'] . "</td>";
        echo "<td>" . $coluna_bd_tabela['usu_indicador_codigo'] . "</td>";
        echo "</tr>";
    }

    echo "</table>";
?>

And this one is the stylized table without the querys working:

<table class="table table-striped projects">
  <thead>
    <tr>
      <th style="width: 1%">#</th>
      <th style="width: 20%">Nome</th>
      <th>Membros Recentes</th>
      <th>Project Progress</th>
      <th>Status</th>
      <th style="width: 20%">#Edit</th>
    </tr>
  </thead>

  <tbody>
    <tr>
      <td>echo $coluna_bd_tabela['usu_codigo']</td>
      <td>
        <a> echo $coluna_bd_tabela['usu_nome']</a>
        <br />
        <small>echo $coluna_bd_tabela['usu_indicou']</small>
      </td>
      <td>
        <ul class="list-inline">
          <li>
            <img src="images/user.png" class="avatar" alt="Avatar">
          </li>
          <li>
            <img src="images/user.png" class="avatar" alt="Avatar">
          </li>
          <li>
            <img src="images/user.png" class="avatar" alt="Avatar">
          </li>
          <li>
            <img src="images/user.png" class="avatar" alt="Avatar">
          </li>
        </ul>
      </td>
      <td class="project_progress">
        <div class="progress progress_sm">
          <div class="progress-bar bg-green" role="progressbar" data-transitiongoal="57"></div>
        </div>
        <small>57% Complete</small>
      </td>
      <td>
        <button type="button" class="btn btn-success btn-xs">Success</button>
      </td>
      <td>
        <a href="#" class="btn btn-primary btn-xs"><i class="fa fa-folder"></i> View </a>
        <a href="#" class="btn btn-info btn-xs"><i class="fa fa-pencil"></i> Edit </a>
        <a href="#" class="btn btn-danger btn-xs"><i class="fa fa-trash-o"></i> Delete </a>
      </td>
    </tr>
  </tbody>

I want to show the stylized table with the values of the querys, but this is destroying me. The database connection is fine, these are the querys on a include connection, they are working fine too, as have been shown on the simple table:

$sql_indicador = "SELECT * FROM esc_usuarios WHERE usu_indicador_codigo = '" . $_SESSION['codigo'] . "'";
$sql_indicador_resul = mysqli_query($conexao, $sql_indicador);

解决方案

To provide a full solution:

<table class="table table-striped projects">
    <thead>
        <tr>
            <th style="width: 1%">#</th>
            <th style="width: 20%">Nome</th>
            <th>Membros Recentes</th>
            <th>Project Progress</th>
            <th>Status</th>
            <th style="width: 20%">#Edit</th>
        </tr>
    </thead>

    <?php while($coluna_bd_tabela = mysqli_fetch_array($sql_indicador_resul)){ ?>
            <tbody>
                <tr>
                    <td><?php echo $coluna_bd_tabela['usu_codigo']; ?></td>
                    <td>
                        <a><?php echo $coluna_bd_tabela['usu_nome']; ?></a>
                        <br />
                        <small><?php echo $coluna_bd_tabela['usu_indicou']; ?></small>
                    </td>
                    <td>
                        <ul class="list-inline">
                            <li>
                                <img src="images/user.png" class="avatar" alt="Avatar">
                            </li>
                            <li>
                                <img src="images/user.png" class="avatar" alt="Avatar">
                            </li>
                            <li>
                                <img src="images/user.png" class="avatar" alt="Avatar">
                            </li>
                            <li>
                                <img src="images/user.png" class="avatar" alt="Avatar">
                            </li>
                        </ul>
                    </td>
                    <td class="project_progress">
                        <div class="progress progress_sm">
                            <div class="progress-bar bg-green" role="progressbar" data-transitiongoal="57"></div>
                        </div>
                        <small>57% Complete</small>
                    </td>
                    <td>
                        <button type="button" class="btn btn-success btn-xs">Success</button>
                    </td>
                    <td>
                        <a href="#" class="btn btn-primary btn-xs"><i class="fa fa-folder"></i> View </a>
                        <a href="#" class="btn btn-info btn-xs"><i class="fa fa-pencil"></i> Edit </a>
                        <a href="#" class="btn btn-danger btn-xs"><i class="fa fa-trash-o"></i> Delete </a>
                    </td>
                </tr>
            </tbody>
    <?php } ?>
</table>

You forgot to use the <?php and ?> opening and closing tags around the echo statements. Furthermore, you missed the ; at the end of each statement. I've also moved the beginning and the end of the table out of PHP's echo since I believe it looks much clearer this way.

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