使用PHP更新XML节点 [英] Updating XML node with PHP

问题描述

我有一个XML文件test.xml

I've an XML file test.xml

<?xml version="1.0"?>
<info>
  <user>
    <name>
      <firstname>FirstName</firstname>
      <lastname>Last Name</lastname>
      <nameCoordinate>
        <xName>125</xName>
        <yName>20</yName>
      </nameCoordinate>
    </name>
  </user>
</info>

我正在尝试更新节点xName& yName在表单提交中使用PHP.因此，我已经使用simplexml_load_file()加载了文件. PHP表单操作代码如下

I'm trying to update the node xName & yName using PHP on a form submission. So, I've loaded the file using simplexml_load_file(). The PHP form action code is below

<?php 
    $xPostName = $_POST['xName'];
    $yPostName = $_POST['yName'];

    //load xml file to edit
        $xml = simplexml_load_file('test.xml');

    $xml->info->user->name->nameCoordinate->xName = $xPostName;
    $xml->info->user->name->nameCoordinate->yName = $yPostName;
    echo "done";
?>

我想更新节点值，但是上面的代码似乎不正确.谁能帮我纠正一下吗?

I want to update the node values but the above code seems to be incorrect. Can anyone help me rectify it??

更新: 我的问题有点类似于使用PHP更新XML文件，但是在这里，我正在从外部文件加载XML，也正在更新元素，而不是属性.那就是我的困惑所在.

UPDATE: My question is somewhat similar to this Updating a XML file using PHP but here, I'm loading the XML from an external file and also I'm updating an element, not an attribute. That's where my confusion lies.

推荐答案

您没有访问正确的节点.在您的示例中，$xml保存根节点<info/>.这里有个很好的提示:始终在XML文档的根节点之后命名用于保存XML文档的变量，这样可以避免此类混淆.

You're not accessing the right node. In your example, $xml holds the root node <info/>. Here's a great tip: always name the variable that holds your XML document after its root node, it will prevent such confusion.

而且，正如Ward Muylaert指出的那样，您需要保存文件.

Also, as Ward Muylaert pointed out, you need to save the file.

这是更正的示例:

// load the document
// the root node is <info/> so we load it into $info
$info = simplexml_load_file('test.xml');

// update
$info->user->name->nameCoordinate->xName = $xPostName;
$info->user->name->nameCoordinate->yName = $yPostName;

// save the updated document
$info->asXML('test.xml');

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