如何使用PHP更新xml文件? [英] How to update xml file using PHP?

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问题描述

我有这样的xml文件-> examples.xml

I have xml file like this --> examples.xml

<?xml version="1.0" encoding="UTF-8"?>
<inventors>
 <person>
 <name>anie</name>
 <comment>good</comment>
 </person>
</inventors>

这是我的php文件-> index.php

This is my php file --> index.php

<script src="http://code.jquery.com/jquery-latest.min.js"></script>
<?php
 $xml = new DOMDocument('1.0', 'utf-8');
 $xml->formatOutput = true;
 $xml->preserveWhiteSpace = false;
 $xml->load('examples.xml');

 //Get item Element
 $element = $xml->getElementsByTagName('person')->item(0);

 //Load child elements
 $name = $element->getElementsByTagName('name')->item(0);
 $comment = $element->getElementsByTagName('comment')->item(0);

 //Replace old elements with new
 $element->replaceChild($name, $name);
 $element->replaceChild($comment, $comment);
 ?>

 <form method="POST" action=''>
  name <input type="text-name" value="<?php echo $name->nodeValue  ?>" name="namanya" />
comment  <input type="text-comment" value="<?php echo $comment->nodeValue  ?>"  name="commentnya"/>
 <input name="submit" type="submit" />
 </form>

 <?php


 if (isset($_POST['submit'])) 
 { 
$name->nodeValue = $_POST['namanya'];
$comment->nodeValue = $_POST['commentnya'];
htmlentities($xml->save('examples.xml'));

 }


 ?>

如果我单击提交"按钮,将无法正常工作,在浏览器视图上有2个结果输入. 如果我单击提交按钮,我希望结果是新输入.

it cant be work if i click button submit, on browser view have 2 result input. if i click button submit, i want result is new input.

推荐答案

您的程序首先显示表单,然后保存数据. 因此,当您单击提交"按钮时,程序将首先显示包含先前数据的表单,然后, 保存新"数据.

Your program shows the form firstly, then saves data secondly. So when you click button submit, the program shows the form with previous data first and then, saves 'new' data.

因此以下代码可以正常工作.

Therefore following code works well.

 <script src="http://code.jquery.com/jquery-latest.min.js"></script>
 <?php
 $xml = new DOMDocument('1.0', 'utf-8');
 $xml->formatOutput = true; 
 $xml->preserveWhiteSpace = false;
 $xml->load('examples.xml');

 //Get item Element
 $element = $xml->getElementsByTagName('person')->item(0);  

 //Load child elements
 $name = $element->getElementsByTagName('name')->item(0);
 $comment = $element->getElementsByTagName('comment')->item(0) ;

 //Replace old elements with new
 $element->replaceChild($name, $name);
 $element->replaceChild($comment, $comment);
 ?>

 <?php
 if (isset($_POST['submit']))
 {
$name->nodeValue = $_POST['namanya'];
$comment->nodeValue = $_POST['commentnya'];
htmlentities($xml->save('examples.xml'));

 }

 ?>

 <form method="POST" action=''>
  name <input type="text-name" value="<?php echo $name->nodeValue  ?>" name="namanya" />
comment  <input type="text-comment" value="<?php echo $comment->nodeValue  ?>"  name="commentnya"/>
 <input name="submit" type="submit" />
 </form>

这篇关于如何使用PHP更新xml文件?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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