PHP strtotime +1个月的行为 [英] PHP strtotime +1 month behaviour
问题描述
我知道PHP函数的有害行为
I know about the unwanted behaviour of PHP's function
strtotime
strtotime
例如，当在日期中添加一个月(+1个月)，例如:31.01.2011-> 2011年3月3日
For example, when adding a month (+1 month) to dates like: 31.01.2011 -> 03.03.2011
我知道它不是正式的 PHP错误 ，解决方案背后有一些争论，但至少对我而言，这种行为在过去和现在都造成了很多时间上的浪费，我个人讨厌它.
I know it's not officially a PHP bug, and that this solution has some arguments behind it, but at least for me, this behavior has caused a lot waste of time (in the past and present) and I personally hate it.
我发现甚至更陌生的是，例如:
What I found even stranger is that for example in:
MySQL :DATE_ADD("2011-01-31"，间隔1个月)返回2011-02-28 或
MySQL: DATE_ADD('2011-01-31', INTERVAL 1 MONTH) returns 2011-02-28 or
C#，其中新的DateTime(2011，01，31).AddMonths(1);将返回28.02.2011
C# where new DateTime(2011, 01, 31).AddMonths(1); will return 28.02.2011
wolframalpha.com 给出31.01.2013 + 1 month作为输入；将于2013年2月28日星期四返回
wolframalpha.com giving 31.01.2013 + 1 month as input; will return Thursday, February 28, 2013
在我看来，其他人已经找到了解决这个愚蠢问题的更合理的解决方案，我在PHP错误报告中看到了很多情况，如果我说我们要在一个月后见面，那将是今天现在"或类似的内容.答案是:如果下个月不存在31，请告诉我该月的最后一天，但请坚持到下个月.
It sees to me that others have found a more decent solution to the stupid question that I saw alot in PHP bug reports "what day will it be, if I say we meet in a month from now" or something like that. The answer is: if 31 does not exists in next month, get me the last day of that month, but please stick to next month.
我的问题是:是否有一个PHP函数(由某人编写)可以解决这个未被官方认可的bug?因为我不认为我是唯一一个在添加/减去月份时想要另一种行为的人.
So MY QUESTION IS: is there a PHP function (written by somebody) that resolves this not officially recognized bug? As I don't think I am the only one who wants another behavior when adding / subtracting months.
我对解决方案特别感兴趣，该解决方案不仅可以在本月底使用，而且可以完全替代strtotime.另外，还应处理strotime +n months的情况.
I am particulary interested in solutions what also work not just for the end of the month, but a complete replacement of strtotime. Also the case strotime +n months should be also dealt with.
祝您编程愉快！
推荐答案
以下是您可以使用的算法.它应该足够简单来实现自己.
Here's the algorithm you can use. It should be simple enough to implement yourself.
- 在变量中具有原始日期和+1个月日期
- 提取两个变量的月份部分
- 如果差异大于1个月(或者原始日期是12月而另一个不是1月)，则将后一个变量更改为下个月的最后一天.例如，您可以在
date()中使用t来获取最后一天:date( 't.m.Y' )
- Have the original date and the +1 month date in variables
- Extract the month part of both variables
- If the difference is greater than 1 month (or if the original is December and the other is not January) change the latter variable to the last day of the next month. You can use for example
tindate()to get the last day:date( 't.m.Y' )
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