PHP随机X位数 [英] php random x digit number

问题描述

我需要创建一个x位数的随机数.

I need to create a random number with x amount of digits.

因此，假设x为5，我需要一个数字，例如. 35562 如果x为3，则它将抛出类似的结果； 463

So lets say x is 5, I need a number to be eg. 35562 If x is 3, then it would throw back something like; 463

有人可以告诉我这是怎么做的吗?

Could someone show me how this is done?

推荐答案

您可以使用 rand() 与 pow() 一起实现: /p>

You can use rand() together with pow() to make this happen:

$digits = 3;
echo rand(pow(10, $digits-1), pow(10, $digits)-1);

这将输出100到999之间的数字.这是因为10 ^ 2 = 100和10 ^ 3 = 1000，然后您需要将其减去一个，以使其处于所需的范围内.

This will output a number between 100 and 999. This because 10^2 = 100 and 10^3 = 1000 and then you need to subtract it with one to get it in the desired range.

如果005也是有效的示例，则可以使用以下代码在其前添加零:

If 005 also is a valid example you'd use the following code to pad it with leading zeros:

$digits = 3;
echo str_pad(rand(0, pow(10, $digits)-1), $digits, '0', STR_PAD_LEFT);

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