从PHP字符串中剥离除字母数字字符外的所有内容 [英] Stripping everything but alphanumeric chars from a string in PHP

问题描述

我想要一个正则表达式或其他字符串，该字符串可以替换字符串中字母数字字符(a-z和0-9)以外的所有内容.诸如,@#$(@*810之类的所有内容都应删除.有什么想法吗?

I'd like a regexp or other string which can replace everything except alphanumeric chars (a-z and 0-9) from a string. All things such as ,@#$(@*810 should be stripped. Any ideas?

现在我需要用它来去除除点以外的所有内容，因此除a-z, 1-9, .以外的所有内容.想法?

I now need this to strip everything but allow dots, so everything but a-z, 1-9, .. Ideas?

推荐答案

$string = preg_replace("/[^a-z0-9.]+/i", "", $string);

匹配一个或多个非a-z 0-9(不区分大小写)或."的字符.并替换为"

Matches one or more characters not a-z 0-9 [case-insensitive], or "." and replaces with ""

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