如何检测文本中的电话号码(并替换它们)? [英] how to detect telephone numbers in a text (and replace them)?

问题描述

我知道可以对不良单词(检查一组预设单词)进行处理，但是如何检测长文本中的电话号码? 我正在用PHP建立一个网站，该网站的客户需要避免使用描述字段输入手机号码的人.(请参阅craigslist等.)

I know it can be done for bad words (checking an array of preset words) but how to detect telephone numbers in a long text? I'm building a website in PHP for a client who needs to avoid people using the description field to put their mobile phone numbers..(see craigslist etc..)

除了他将需要一些节制，但我想知道是否有办法阻止至少像nnn-nnn-nnnn这样的显而易见的东西，而不是要阻止像HeiGHT*/four*/nine这样的其他怪异的写作方式...

beside he's going to need some moderation but i was wondering if there is a way to block at least the obvious like nnn-nnn-nnnn, not asking to block other weird way of writing like HeiGHT*/four*/nine etc...

推荐答案

欢迎来到正则表达式领域.基本上，您将要使用preg_replace查找(某种模式)并替换为字符串.

Welcome to the world of regular expressions. You're basically going to want to use preg_replace to look for (some pattern) and replace with a string.

以下是一些可以让您开始的东西:

Here's something to start you off:

$text = preg_replace('/\+?[0-9][0-9()\-\s+]{4,20}[0-9]/', '[blocked]', $text);

这寻找:

加号(可选)，后跟一个数字，然后是4-20个数字，方括号，破折号或空格，然后是一个数字

a plus symbol (optional), followed by a number, followed by between 4-20 numbers, brackets, dashes or spaces, followed by a number

并替换为字符串[blocked].

and replaces with the string [blocked].

这捕获了所有我能想到的明显组合:

This catches all the obvious combinations I can think of:

012345 123123
[phone]
[phone]
0123456789
Placename 123456 (although this one will leave 'Placename')

但是，它还会去除连续的6个以上的数字，这可能是不希望的！

however it will also strip out any succession of 6+ numbers, which might not be desirable!

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