正则表达式提取2个花括号之间的字符串 [英] Regex extract string between 2 curly braces
问题描述
我有以下短代码:
亲爱的
{{name}}
,
正在邀请您参加以下活动:{{event}}
You are being invited for the following event: {{event}}
致谢,{{author}}
我有一个来自数据库的数组:
$data
I have an array from the database :
$data
其中:
$data['name'] = 'John Doe';
$data['event'] = 'Party yay!';
$data['author'] = 'Kehke Lunga';
我期望的输出:
尊敬的John Doe,
Dear John Doe,
您受邀参加以下活动:派对!!
You are being invited for the following event: Party yay!
致谢Kehke Lunga
regards, Kehke Lunga
此外,我还想执行类似{{firstname||lastname}}
的操作,该操作应检查是否已设置键$data['firstname']
,如果未设置,则应使用$data['lastname']
.但是,这是以后的事情.
also, I also want to perform operations like {{firstname||lastname}}
which should either check if key $data['firstname']
is set, if it isn't it should use $data['lastname']
. However, that is for later stage.
现在,我只想知道如何在2个花括号之间匹配文本.
For now, I just want to know how to match the text between 2 curly braces.
谢谢
推荐答案
对于第二个操作,您可能需要这样:
And for the second operations you need it could be something this way:
$str = "Dear {{name||email}}, You are being invited for the following event: {{event}}. Regards, {{author}}";
// $data['name'] = 'John Doe';
$data['email'] = 'JohnDoe@unknown.com';
$data['event'] = 'Party yay!';
$data['author'] = 'Kehke Lunga';
$pattern = '/{{(.*?)[\|\|.*?]?}}/';
$replace = preg_replace_callback($pattern, function($match) use ($data)
{
$match = explode('||',$match[1]);
return isset($data[$match[0]]) ? $data[$match[0]] : $data[$match[1]] ;
}, $str);
echo $replace;
基本上,通过编辑"$ pattern",然后在回调中找到所需的正确逻辑.
Basically by editing the '$pattern', and then find the correct logic needed inside the callback.
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