Pickle.dump到变量 [英] Pickle.dump to variable

问题描述

我是python的新手，我想知道是否有解决此问题的方法:

I'm new in python and i wanted to know if there is a solution for this problem:

我知道这听起来很奇怪，但是我想将pickle.dump数据保存到变量中. 我开始认为我可以通过创建一个伪造的类来绕过它，而不是写一个文件，写一个变量:

I know that this may sound strange but i want to save the pickle.dump data into a variable. I begin to think that may i could bypass it by making a fake class to instead of writing in a file, writing in a variable:

class PickleDatatoVar(object):
def __init__(self):
    self.data = None
def write(self, data):
    self.data = data
def get(self):
    return self.data

然后:

pick = PickleDatatoVar()
pickle.dump(Int, pick)
var = pick.get()

什么都没有显示为错误，但是输出只是一个'.'

Nothing is presented as error, but the output is just a '.'

那么有解决方案，而不是将其保存在文件中保存为变量吗?

So is there a solution to instead of saving that in a file saving into a variable?

推荐答案

您正在寻找内存文件对象；在Python 2中 cStringIO.StringIO() ，对于Python 3

You are looking for an in-memory file object; in Python 2 that's cStringIO.StringIO(), for Python 3 io.BytesIO(); these act just like file objects and you can have pickle.dump() write to these.

但是，更简单的方法是使用 pickle.dumps() 直接转储到字符串对象.

However, the easier path would be to use pickle.dumps() to dump straight to a string object instead.

内幕，pickle.dumps()为您执行的操作是创建一个内存文件对象，向其中写入泡菜数据，并为您检索字符串结果；参见源代码:

Under the hood, what pickle.dumps() does for you is create an in-memory file object, write the pickle data to it and retrieve the string result for you; see the source code:

def _dumps(obj, protocol=None, *, fix_imports=True):
    f = io.BytesIO()
    _Pickler(f, protocol, fix_imports=fix_imports).dump(obj)
    res = f.getvalue()
    assert isinstance(res, bytes_types)
    return res

但是通过这种方式，您不必自己做额外的工作.

but this way you don't have to do that extra work yourself.

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