加载所有腌制对象 [英] Load all pickled objects

问题描述

import pickle

ListNames = [["Name1","City1","Email1"],["Name2","City2","Number2"]]
ListNumbers = [1,2,3,4,5,6,7,8]

with open ("TestPickle.pickle","wb") as fileSaver:
    pickle.dump(ListNames,fileSaver)
    pickle.dump(ListNumbers,fileSaver)

with open ("TestPickle.pickle","rb") as fileOpener:
    print(pickle.load(fileOpener))

输出为:

[['Name1', 'City1', 'Email1'], ['Name2', 'City2', 'Number2']]

我怎么也要泡菜来加载ListNumbers

How do I get pickle to load the ListNumbers too

我知道我可以再次打印pickle.load，但是如果我在pickle文件中有数量不明的项目，并且具有许多数据类型(例如:列表，元组，字典，字符串...)，该怎么办

I know I can just print pickle.load again but what if I have an unknown number of items in my pickle file with a number of Datatypes (e.g: lists, tuples, dictionaries, strings....)

谢谢

推荐答案

我不确定这是否是正确的方法.

I am not sure if this i the correct approach.

import pickle

ListNames = [["Name1","City1","Email1"],["Name2","City2","Number2"]]
ListNumbers = [1,2,3,4,5,6,7,8]

with open ("TestPickle.pickle","wb") as fileSaver:
    pickle.dump(ListNames,fileSaver)
    pickle.dump(ListNumbers,fileSaver)
obj = []
with open("TestPickle.pickle","rb") as fileOpener:
    while True:
        try:
            obj.append(pickle.load(fileOpener))
        except EOFError:
            break
print obj

输出:

[[['Name1', 'City1', 'Email1'], ['Name2', 'City2', 'Number2']], [1, 2, 3, 4, 5, 6, 7, 8]]

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