具有数据的cPickle类保存到文件 [英] cPickle class with data save to file

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本文介绍了具有数据的cPickle类保存到文件的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在Python中有一个大类,它是类数据库"类.我想将其保存到文件-全部包括数据.

I've big class in Python it's "DataBase-like" class. I want to save it to file - all including data.

这是输入(显示问题的示例,在脚本数据库中类似10000条记录):

This is input(example to show the issue, in script database is like 10000 records):

import cPickle
# DataBase-like class
class DataBase:
    class Arrays: pass
    class Zones: pass
    class Nodes: 
        class CR: pass    
    class Links: 
        class CR: pass
    class Turns:
        class CR: pass    
    class OrigConnectors: pass
    class DestConnectors: pass    
    class Paths: pass
    pass
# some basic input into database
DataBase.Arrays.Data=[]
for i in range(1000):
    DataBase.Arrays.Data.append([i+4]) 

print DataBase.Arrays.Data[56]

# and now I want to save it to file

import cPickle    

filename='D:/results/file.lft'
file=open(filename,'w')
cPickle.dump(DataBase, file, protocol=2)`

这就是我得到的文件:

€c__main__
DataBase
q.`

没有数据,只有定义.我该如何克服.也许将数据保存为类不是一个好主意吗?

There's no data, just definition. How can I overcome that. Maybe saving my data as a class is not a good idea?

推荐答案

您正在腌制作为类定义的"DataBase".您需要实例化DataBase类的对象,然后对其进行腌制.

You are pickling "DataBase" which is a class definition. You need to instantiate an object of class DataBase then pickle that.

objDataBase = DataBase()
objDataBase.Arrays.Data = etc....

filename='D:/results/file.lft'
file=open(filename,'w')
cPickle.dump(objDataBase, file, protocol=2)
file.close()

这篇关于具有数据的cPickle类保存到文件的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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