如何使用十六进制字符串更改R中饼图中的切片颜色? [英] How can I change the colors of the slices in pie charts in plotly for r using hexadecimal strings?

问题描述

这是我目前的饼图:

library(plotly)
library(RColorBrewer)


P <- data.frame (labels = c("A", "B", "C", "D", "E"),
             values = c(5, 8, 3, 4, 9))

plot_ly(P, labels = labels, values = values, type = "pie",
    marker = list(colors=c("lightskyblue", "deepblue", "dodgerblue", "midnightblue", "powderblue")),
    textinfo="value",
    textposition="outside") 

我想用十六进制字符串更改其颜色，以便可以使用RColorBrewer中的调色板.预先谢谢你！

I wanted to change its colors with hexidecimal strings so I could use palettes from RColorBrewer. Thank you in advance!

推荐答案

只需将十六进制值放入字符串中，并在其前面加上一个哈希(磅符号)#.十六进制的前两位数字表示红色，后两位数字表示绿色，然后两位数字表示蓝色(#RRGGBB). (可选)您可以为透明度(#RRGGBBAA)添加额外的两位数字.

Just put the hex values into the strings, preceded with a hash (pound symbol) #. the first two digits in hex are for red, the next 2 for green, then 2 digits for blue (#RRGGBB). Optionally you can add an extra two digits for the alpha (transparency) (#RRGGBBAA).

例如

plot_ly(P, labels = labels, values = values, type = "pie",
    marker = list(colors=c("#556677", "#AA3344", "#772200", 
                           "#11AA22", "#AA231B88")), # the last color has alpha value set.
    textinfo="value",
    textposition="outside") 

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