在PIL中创建棋盘 [英] Creating a chessboard in PIL

问题描述

我一直试图在PIL模块中创建一个棋盘，我已经获得了前两行的常规模式，但是无法弄清楚如何将其应用于整个棋盘.如您所见，我创建了一个图像:

I have been trying to create a chessboard in the PIL module and I have got the general pattern for the first two rows, but can't figure out how to apply this to the entire board. As you can see, I have created an image:

from PIL import Image

img = Image.new("RGB", (15,15), "white") # create a new 15x15 image
pixels = img.load() # create the pixel map

我对前两行的解决方案

注意-我仍在学习Python，因此此代码似乎效率很低，但可以随时提出改进建议.

My solution for the first two rows

Note - I am still learning Python so this code may seem very inefficient, but feel free to suggest improvements.

代码:

black_2 = []
for i in range(img.size[0]):
    if i % 2 == 0:
        black_2.append(i)

这给了我所有放置黑色像素的水平索引位置.因此，对于我创建的15x15电路板，它返回[0, 2, 4, 6, 8, 10, 12, 14]

This gives me all the horizontal index positions on where to put a black pixel. Therefore, for the 15x15 board I created, it returns [0, 2, 4, 6, 8, 10, 12, 14]

代码:

然后我使用第二行计算出第一行的水平索引位置

I then use the second row to work out the horizontal index positions for the first row

black_1 = [i-1 for i in black_2 if i > 0]
if img.size[0] % 2 == 0: # 'that' if statement
    black_1.append(img.size[0]-1)

对于我创建的15x15像素板，它返回[1, 3, 5, 7, 9, 11, 13].我创建了if语句，因为我意识到如果木板长度均匀，最后一个黑色像素不会显示出来，那似乎可以解决这个问题.

For the 15x15 pixel board I created, it returns [1, 3, 5, 7, 9, 11, 13]. I created that if statement because I realised that the last black pixel was not showing if the board had an even length, and that seemed to fix it.

# hardcoded to check patterns
for i in black_1:
    pixels[i,0] = (0,0,0)

for k in black_2:
    pixels[k,1] = (0,0,0)

img.show()

无论大小如何如何将这两种图案都应用到电路板的其余部分?

How can I apply both patterns to the rest of the board, regardless of its size?

我怀疑需要一个for var in range()循环，但是我不确定它会如何变化，具体取决于板的高度(img.size[1])是奇数还是偶数.

I would suspect a for var in range() loop is needed, but I am not sure how it would change depending on if the height(img.size[1]) of the board is odd or even.

black_1适用于第一行

black_2适用于第二行

推荐答案

一个国际象棋棋盘有64个正方形而不是256个正方形.首先需要(8,8)，然后可以使用double for循环将颜色分配给所有8行.

A chess board has 64 squares instead of 256. Firstly you need (8,8) and then you can use double for loops to assign the color to all the 8 rows.

任何大小的常规示例

from PIL import Image

size = 16
img = Image.new("RGB", (size,size), "white") # create a new 15x15 image
pixels = img.load() # create the pixel map

black_2 = []
for i in range(img.size[0]):
    if i % 2 == 0:
        black_2.append(i)

black_1 = [i-1 for i in black_2 if i > 0]
if img.size[0] % 2 == 0: # 'that' if statement
    black_1.append(img.size[0]-1)


for i in black_1:
    for j in range(0, size, 2):
        pixels[i,j] = (0,0,0)

for k in black_2:
    for l in range(1, size+1, 2):
        pixels[k,l] = (0,0,0)

img.show()

这篇关于在PIL中创建棋盘的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！