使用python在pygame中制作8 * 8棋盘 [英] Make a 8*8 chessboard in pygame with python

问题描述

我想用python在pygame中制作一个棋盘.仅带有for循环的棋盘.我尝试了几种方法来做到这一点，但是我没有弄清楚到底是什么.这是我的代码:

I want to make a chessboard in pygame with python. Just only the chessboard with for loops. I tried in several ways to do this but i didn't figured out what exactly it will be. Here is my code:

import pygame
pygame.init()

#set color with rgb
white,black,red = (255,255,255),(0,0,0),(255,0,0)

#set display
gameDisplay = pygame.display.set_mode((800,600))

#caption
pygame.display.set_caption("ChessBoard")

#beginning of logic
gameExit = False

lead_x = 20
lead_y = 20

while not gameExit:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            gameExit = True

#For loop for chessboard 

#draw a rectangle
gameDisplay.fill(white)
pygame.draw.rect(gameDisplay, black, [lead_x,lead_y,20,20])
pygame.display.update()


#quit from pygame & python
pygame.quit()
quit()

现在我需要专家建议，Python代码将是什么.我只是想在屏幕上显示一个棋盘.就是这样.

Now i need an expert suggestion what it will be with python code. I just wanna show a chessboard in my screen. Thats it.

推荐答案

可能的解决方案，也许不是最优雅的，但是您可以循环创建正方形

Possible solution, maybe not the most elegant, but you can create the squares in a loop

#Size of squares
size = 20

#board length, must be even
boardLength = 8
gameDisplay.fill(white)

cnt = 0
for i in range(1,boardLength+1):
    for z in range(1,boardLength+1):
        #check if current loop value is even
        if cnt % 2 == 0:
            pygame.draw.rect(gameDisplay, white,[size*z,size*i,size,size])
        else:
            pygame.draw.rect(gameDisplay, black, [size*z,size*i,size,size])
        cnt +=1
    #since theres an even number of squares go back one value
    cnt-=1
#Add a nice boarder
pygame.draw.rect(gameDisplay,black,[size,size,boardLength*size,boardLength*size],1)

pygame.display.update()

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