管道数据到命令行PHP? [英] piping data into command line php?
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问题描述
是否可以使用Unix管道将数据管道传输到命令行php脚本中?我已经尝试过
It is possible to pipe data using unix pipes into a command-line php script? I've tried
$> data | php script.php
但是预期的data
没有出现在$argv
中.有办法吗?
But the expected data
did not show up in $argv
. Is there a way to do this?
推荐答案
据我了解,$argv
将显示程序的参数,换句话说:
As I understand it, $argv
will show the arguments of the program, in other words:
php script.php arg1 arg2 arg3
但是,如果将数据通过管道传输到PHP,则必须从标准输入中读取数据.我从来没有尝试过,但是我认为是这样的:
But if you pipe data into PHP, you will have to read it from standard input. I've never tried this, but I think it's something like this:
$fp = readfile("php://stdin");
// read $fp as if it were a file
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