POST文件Curl命令行到PHP Curl [英] POST file Curl Commandline to PHP Curl
本文介绍了POST文件Curl命令行到PHP Curl的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我们正在尝试使用下面的curl cmdline进行转换，
We are trying to convert use the following curl cmdline which is working fine
curl --request POST --data-binary @"/home/project/enrol/my.wav" --header "Content-Type:audio/wav" --header "VsitEmail: 200037test2@test.com" --header "VsitPassword: 8270f2824111e04d9278c01a92b388147d9d02e0b50d946d25d00db375ff1282" --header "VsitDeveloperId: 200037" https://siv.voiceprintportal.com/sivservice/api/enrollments
到PHP libcurl，该库不断出现内部错误.
to PHP libcurl which is constantly giving internal error.
请指出我错了.
代码
$ch = curl_init();
$path="/home/project/enrol/my.wav";
curl_setopt($ch, CURLOPT_URL,$url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_POST,true);
curl_setopt($ch, CURLOPT_BINARYTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, array("Content-Type: audio/wav","VsitEmail: 200037test2@test.com","VsitPassword: 8270f2824111e04d9278c01a92b388147d9d02e0b50d946d25d00db375ff1282","VsitDeveloperId: 200037"));
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt( $ch , CURLOPT_VERBOSE , 0 );
curl_setopt($ch, CURLOPT_POSTFIELDS,array('file' => '@'.$path));
$result = curl_exec($ch);
//close connection
curl_close($ch);
print_r($result);
更新1
$localfile='/home/project/enrol/my.wav';
$url = 'https://siv.voiceprintportal.com/sivservice/api/enrollments';
$ch = curl_init();
$fields = array('file' => '@' .$localfile);
$resource = curl_init();
curl_setopt($resource, CURLOPT_URL, $url);
//curl_setopt($resource, CURLOPT_HTTPHEADER, $header);
curl_setopt($resource, CURLOPT_HTTPHEADER, array("Content-Type:
audio/wav","VsitEmail: 200037test2@test.com","VsitPassword: 8270f2824111e04d9278c01a92b388147d9d02e0b50d946d25d00db375ff1282","VsitDeveloperId: 200037"));
curl_setopt($resource, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($resource, CURLOPT_POST, 1);
curl_setopt($resource, CURLOPT_BINARYTRANSFER, true);
curl_setopt($resource, CURLOPT_POSTFIELDS, $fields);
//$result = json_decode(curl_exec($resource));
$result=curl_exec($resource);
curl_close($resource);
echo "The result is";
print_r($result);
推荐答案
通过传递原始数据文件而不是数组来解决该问题.正确的代码是
It got resolved by passing the raw data file instead of an array. Correct code is
$localfile='@/home/project/enrol/my.wav';
$url = 'https://siv.voiceprintportal.com/sivservice/api/enrollments';
$data = file_get_contents('/home/project/enrol/my.wav');
$headers = array();
$headers[] = 'X-Requested-With: JSONHttpRequest';
$headers[] = 'Content-Type: audio/wav';
$headers[] = 'VsitEmail: 200037test2@test.com';
$headers[] = 'VsitPassword: 8270f2824111e04d9278c01a92b388147d9d02e0b50d946d25d00db375ff1282';
$headers[] = 'VsitDeveloperId: 200037';
$resource = curl_init();
curl_setopt($resource, CURLOPT_URL, $url);
curl_setopt($resource, CURLOPT_HTTPHEADER,$headers);
curl_setopt($resource, CURLOPT_POST,1);
curl_setopt($resource, CURLOPT_BINARYTRANSFER, true);
curl_setopt($resource, CURLOPT_POSTFIELDS,$data);
$result = json_decode(curl_exec($resource));
curl_close($resource);
echo "The result is";
print_r($result);
这篇关于POST文件Curl命令行到PHP Curl的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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