如何将curl文件从命令行转换为PHP cURL [英] How to convert curl file post from command line into PHP cURL

问题描述

我试图从我的PHP应用程序发布文件到第三方API。
这可以从命令行下载：

  curl -Ffile=@move_file.MOVhttps：/ /upload.wistia.com?project_id=pbmcmua3ot&username=api&api_password=xxxxx_apikey_yyyyy
  

但是我无法使用PHP的curl工作：

  $ data = array（
'username'=> $ username，
'api_password'=> $ api_password，$ b $'file'=> fopen（$ tmp_filename，'r'），
'project_id'=> $ project_hashed_id，
）; 
 
 
 $ ch = curl_init（）; 
 // curl_setopt（$ ch，CURLOPT_POST，1）; 
 curl_setopt（$ ch，CURLOPT_RETURNTRANSFER，1）; 
 curl_setopt（$ ch，CURLOPT_URL，https://upload.wistia.com）; 
 curl_setopt（$ ch，CURLOPT_UPLOAD，1）; 
 curl_setopt（$ ch，CURLOPT_TIMEOUT，86400）; // $ 1 Day Timeout 
 
 curl_setopt（$ ch，CURLOPT_INFILE，fopen（$ tmp_filename，'r'））; 
 curl_setopt（$ ch，CURLOPT_NOPROGRESS，false）; 
 curl_setopt（$ ch，CURLOPT_BUFFERSIZE，128）; 
 curl_setopt（$ ch，CURLOPT_INFILESIZE，filesize（$ tmp_filename））; 
 
 curl_setopt（$ ch，CURLOPT_VERBOSE，1）; //用于调试
 curl_setopt（$ ch，CURLOPT_HEADER，true）; 
 
 curl_setopt（$ ch，CURLOPT_POSTFIELDS，http_build_query（$ data））; 
 
 $ result = curl_exec（$ ch）; 
 curl_close（$ ch）; 
返回json_decode（$ result）; 
  

我认为 CURLOPT_INFILE 我不确定。
$ b

UPDATE1

<$ p $感谢您提供任何帮助， $ data = array（
'username'=> $ username，
'api_password'=> $ api_password，
'file'=>' @'。$ tmp_filename，
'project_id'=> $ project_hashed_id，
）;

$ ch = curl_init（）;
curl_setopt（$ ch，CURLOPT_POST，1）;
curl_setopt（$ ch，CURLOPT_RETURNTRANSFER，1）;
curl_setopt（$ ch，CURLOPT_URL，https://upload.wistia.com）;
curl_setopt（$ ch，CURLOPT_UPLOAD，1）;
curl_setopt（$ ch，CURLOPT_TIMEOUT，86400）; // 1 Day Timeout
curl_setopt（$ ch，CURLOPT_NOPROGRESS，false）;
curl_setopt（$ ch，CURLOPT_BUFFERSIZE，128）;
curl_setopt（$ ch，CURLOPT_INFILESIZE，filesize（$ tmp_filename））;
curl_setopt（$ ch，CURLOPT_VERBOSE，1）; //用于调试
curl_setopt（$ ch，CURLOPT_HEADER，true）;
curl_setopt（$ ch，CURLOPT_POSTFIELDS，$ data）;

$ result = curl_exec（$ ch）;
curl_close（$ ch）;
返回json_decode（$ result）;


更新2（工作）
$ $ b $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $'$'$'$'$'$'$'$'$ $ $'$'
'project_id'=> $ project_id
）;

$ ch = curl_init（）;
curl_setopt（$ ch，CURLOPT_POST，1）;
curl_setopt（$ ch，CURLOPT_URL，https://upload.wistia.com）;
curl_setopt（$ ch，CURLOPT_POSTFIELDS，$ data）;
$ result = curl_exec（$ ch）;
curl_close（$ ch）;

解决方案

，只要有

  $ data = array（
'file'=>'@ move_file.MOV'
）; 
  

Curl会看到 @ 作为文件上传尝试。你也不必做 http_build_query（）。 curl可以直接接受一个数组，并且可以构建自己的查询：
$ b $ $ $ p $ curl_setopt（$ ch，CURLOPT_POSTFIELDS，$ data）;

I'm trying to post files to a 3rd party API from my PHP app. This works from the command line:

curl -F "file=@move_file.MOV" "https://upload.wistia.com?project_id=pbmcmua3ot&username=api&api_password=xxxxx_apikey_yyyyy"

But I can't get it to work using PHP's curl:

    $data = array(
        'username'      => $username,
        'api_password'  => $api_password,
        'file'          => fopen($tmp_filename, 'r'),
        'project_id'    => $project_hashed_id,
        );


    $ch = curl_init();
    //curl_setopt($ch, CURLOPT_POST, 1);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_URL, "https://upload.wistia.com" );
    curl_setopt($ch, CURLOPT_UPLOAD, 1);
    curl_setopt($ch, CURLOPT_TIMEOUT, 86400); // 1 Day Timeout

    curl_setopt($ch, CURLOPT_INFILE, fopen($tmp_filename, 'r') );
    curl_setopt($ch, CURLOPT_NOPROGRESS, false);
    curl_setopt($ch, CURLOPT_BUFFERSIZE, 128);
    curl_setopt($ch, CURLOPT_INFILESIZE, filesize($tmp_filename));

    curl_setopt($ch, CURLOPT_VERBOSE, 1); //for debugging
    curl_setopt($ch, CURLOPT_HEADER, true);

    curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($data));

    $result = curl_exec($ch);
    curl_close($ch);
    return json_decode($result);

I think CURLOPT_INFILE is the problem but I'm not sure. Thanks in advance for any help you can give me.

UPDATE1

    $data = array(
        'username'      => $username,
        'api_password'  => $api_password,
        'file'          => '@'.$tmp_filename,
        'project_id'    => $project_hashed_id,
        );

    $ch = curl_init();
    curl_setopt($ch, CURLOPT_POST, 1);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_URL, "https://upload.wistia.com" );
    curl_setopt($ch, CURLOPT_UPLOAD, 1);
    curl_setopt($ch, CURLOPT_TIMEOUT, 86400); // 1 Day Timeout
    curl_setopt($ch, CURLOPT_NOPROGRESS, false);
    curl_setopt($ch, CURLOPT_BUFFERSIZE, 128);
    curl_setopt($ch, CURLOPT_INFILESIZE, filesize($tmp_filename));
    curl_setopt($ch, CURLOPT_VERBOSE, 1); //for debugging
    curl_setopt($ch, CURLOPT_HEADER, true);
    curl_setopt($ch, CURLOPT_POSTFIELDS, $data);

    $result = curl_exec($ch);
    curl_close($ch);
    return json_decode($result);

UPDATE 2 (Working)

    $data = array(
        'api_password'  => $api_password,
        'file'          => '@'.$tmp_filename,
        'project_id'    => $project_id
        );

    $ch = curl_init();
    curl_setopt($ch, CURLOPT_POST, 1);
    curl_setopt($ch, CURLOPT_URL, "https://upload.wistia.com" );
    curl_setopt($ch, CURLOPT_POSTFIELDS, $data);    
    $result = curl_exec($ch);
    curl_close($ch);

解决方案

You don't need to open a handle for curl, just have

$data = array(
    'file' => '@move_file.MOV'
);

Curl will see the @ and treat it as a file upload attempt. You also don't have to do http_build_query() either. Curl can accept an array directly and do the query building itself:

curl_setopt($ch, CURLOPT_POSTFIELDS, $data);

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