如何在Python中读取给定像素的RGB值? [英] How to read the RGB value of a given pixel in Python?

问题描述

如果使用open("image.jpg")打开图像，假设我具有像素的坐标，如何获得像素的RGB值?

If I open an image with open("image.jpg"), how can I get the RGB values of a pixel assuming I have the coordinates of the pixel?

然后，我该怎么做呢?从空白图形开始，写入"具有一定RGB值的像素吗?

Then, how can I do the reverse of this? Starting with a blank graphic, 'write' a pixel with a certain RGB value?

如果我不需要下载任何其他库，我会希望.

I would prefer if I didn't have to download any additional libraries.

推荐答案

最好使用 Python图片库要执行此操作，恐怕是单独下载.

It's probably best to use the Python Image Library to do this which I'm afraid is a separate download.

最简单的方法是通过Image对象上的 load()方法会返回一个像素访问对象，您可以像数组一样对其进行操作:

The easiest way to do what you want is via the load() method on the Image object which returns a pixel access object which you can manipulate like an array:

from PIL import Image

im = Image.open('dead_parrot.jpg') # Can be many different formats.
pix = im.load()
print im.size  # Get the width and hight of the image for iterating over
print pix[x,y]  # Get the RGBA Value of the a pixel of an image
pix[x,y] = value  # Set the RGBA Value of the image (tuple)
im.save('alive_parrot.png')  # Save the modified pixels as .png

或者，查看 ImageDraw ，它提供了更丰富的API，可用于创建图像.

Alternatively, look at ImageDraw which gives a much richer API for creating images.

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