如何在 Python 中读取给定像素的 RGB 值? [英] How to read the RGB value of a given pixel in Python?

问题描述

如果我用 open("image.jpg") 打开一个图像，假设我有像素的坐标，我如何获得像素的 RGB 值?

If I open an image with open("image.jpg"), how can I get the RGB values of a pixel assuming I have the coordinates of the pixel?

那么，我该如何做相反的事情呢?从一个空白图形开始，写"一个具有特定 RGB 值的像素?

Then, how can I do the reverse of this? Starting with a blank graphic, 'write' a pixel with a certain RGB value?

如果我不必下载任何其他库，我会更喜欢.

I would prefer if I didn't have to download any additional libraries.

推荐答案

最好使用 Python图像库要做到这一点，恐怕是一个单独的下载.

It's probably best to use the Python Image Library to do this which I'm afraid is a separate download.

最简单的方法是通过 Image 对象上的 load() 方法 返回一个像素访问对象，您可以像数组一样操作它:

The easiest way to do what you want is via the load() method on the Image object which returns a pixel access object which you can manipulate like an array:

from PIL import Image

im = Image.open('dead_parrot.jpg') # Can be many different formats.
pix = im.load()
print im.size  # Get the width and hight of the image for iterating over
print pix[x,y]  # Get the RGBA Value of the a pixel of an image
pix[x,y] = value  # Set the RGBA Value of the image (tuple)
im.save('alive_parrot.png')  # Save the modified pixels as .png

或者，查看 ImageDraw，它为创建图像提供了更丰富的 API.

Alternatively, look at ImageDraw which gives a much richer API for creating images.

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