在Python或C ++中获得像素颜色的最快方法? [英] Fastest way to get pixel color in Python or C++?

问题描述

我正在尝试向正在制作的透明Tkinter小部件中添加模糊效果.

I'm trying to add a blur effect to a transparent Tkinter widget I'm making.

我使用此行(代码段)使小部件部分透明

I made the widget partially transparent with this line (snippet)

self.attributes("-alpha", 0.85)

要添加效果，我需要获取小部件中每个像素的RGB值.看到小部件只是部分不透明，我不能使用 .cget 方法，因为它返回它的填充RGB值(将其变为部分透明之前的颜色)，而不是它的实际RGB值).

In order to add the effect I desire I need to get the RGB values of each individual pixel in the widget. Seeing as the widget is only partially opaque I can not use the .cget method because it returns it's fill RGB value (the color before it's made partially transparent), not it's actual RGB value).

我当前正在使用此功能(摘要)

I currently am using this function (snippet)

def get_pixel_colour(self, i_x, i_y):
    i_desktop_window_id = win32gui.GetDesktopWindow()
    i_desktop_window_dc = win32gui.GetWindowDC(i_desktop_window_id)
    long_colour = win32gui.GetPixel(i_desktop_window_dc, i_x, i_y)
    i_colour = int(long_colour)
    return (i_colour & 0xff), ((i_colour >> 8) & 0xff), ((i_colour >> 16) & 0xff)

但是，对于我来说，太远太慢了.有没有更快的方法来获得像素颜色?

However, it is far too slow for my purposes. Is there any faster way to get pixel color?

如果Python为此目的太慢，我也可以使用C ++. 我只需要获取不同x，y坐标下像素的RGB值.

If Python is just too slow for this purpose, I can also use C++. I just need to get the RGB values of pixels at different x, y coordinates.

推荐答案

您不妨看一看Python Image Library，您可以将其命名为

You may wish to take a look at the Python Image Library you could call something like this

import Image
im = Image.open("name_of_file.jpg")
list_of_pixels = list(im.getdata())
print list_of_pixels[0]

这将以RGB格式输出第一个像素，例如(255,255,255) 它相当快，但是我相信它永远不会击败C ++

That would output the very first pixel in a RGB format like (255,255,255) It is pretty fast but it wont ever beat C++ I believe

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